a. A shear vane test, done on a deposit of soft alluvial clay required a torque of 67.5 Nm. The dimensions of the vane were: D = 75 mm; H= 150 mm. What is the value for the undrained %3D shear strength of this clay soil?. 160 KN lun?
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- SITUATION 5: A sand sample is subjected to direct shear testing at it's (in - situ) water content. Two tests are performed. For one of the tests, the sample shears at a stress of 400 kPa when the normal stress is 600 kPa. From these data, 15. Determine the value of the apparent cohesion. c. 230 kPa d. 221 kPa а. 100 kPa b. 179 КРа 16. Determine the corresponding angle of internal friction. a. 22.65 degrees b. 26.57 degrees c. 32.54 degrees d. 18.43 degreesA vane shear test was performed on saturated clay layer at the site and it is noted that a torque of 45 N-m was required to shear the soil. In order to remould the soil, the vane was rotated rapidly under the certain value of torque say "x". If the sensitivity of the clay is 8, then calculate the value of "x" in N-m. Assume diameter and length of the vane to be 70 mm and 130 mm respectively, consider two way shearing,the results of a consolidated undrained test, in which o3 = 392 kN/m?, %3D on a normally consolidated clay are given next: Axial Strain, % Ao, kN/m2 Ud, kN/m? 0.5 156 99 0.75 196 120 1 226 132 1.3 235 147 2 250 161 3 245 170 4 240 173 4.5 235 175 Draw the kf line in a p' vs q' diagram. Also draw the stress path for the test in the diagram.
- In a tri –axial test of a silty soil, the sample failed at normal stress of 475 kPa and a shear stress of 350 kPa.1. Which of the following gives the angle of internal friction? a. 36.4 degreesb. 46.3 degreesc. 39.3 degreesd. 26.3 degrees2. Find the angle that the failure plane makes with the x-axis.a. 36.3 degreesb. 63.2 degreesc. 69.3 degreesd. 76.3 degrees3. Find the maximum failure stress. a. 1280.72 kPab. 1210.72 kPac. 1169.41 kPad. 1250.72 kPa1. Triaxial compression tests are done on quartzite rocks, the results are shown below. (0₁+03)/2 -964.25 14500 19575 23200 29000 43210 63075 psi (01-03)/2 964.25 14500 18850 21750 26100 35960 48575 psi Comment on the applicability of each of the Mohr-Coulomb, Griffith, and Hoek-Brown criteria for the testing results.A CD triaxial test was conducted on a loose sand. The axial stress was held constant and the radial stress was increased until failure occurred. At critical state, the radial stress was greater than the axial stress. Show that, using Mohr’s circle and geometry, the slip plane is inclined at (π/2)/2-fcs¢/2 to the horizontal plane.
- SITUATION 14: After conducting a tri-axial test on a sand sample, the normal and shearing stresses on the failure plane at failure were found to be 400 kPa and 350 kPa respectively.48. Which of the following gives the angle of shearing resistance? a. 38.79 b. 41.19 c. 48.81 d. 53.949. Which of the following most nearly gives the angle of failure plane measured from the major principal plane?a. 69.41 b. 64.40 c. 71.99 d. 65.5950. Which of the following most nearly gives the major principal stress? a. 1331.51 Kpa b. 1414.58 Kpa c. 1130.37 Kpa d. 1171.32 KpA field vane shear test was conducted in saturated clay. The height and diameter of the vane were 101.6 mm and 50.8 mm respectively. During the test, the maximum torque applied was 0.0168 kN.m Determine the undrained shear strength of the clay? The clay soil described above has a liquid limit of 64 and a plastic limit of 29. What is the plasticity index?1.A dry sand is known to have an angle of internal friction of 29. A triaxial test is planned, where the confining pressure will be 41 kPa. What is the maximum axial stress, in kPa, (major principal stress) that can be applied? Calculate the value to 1 decimal place. Do not provide units in your answer. 2.A clay soil is subjected to a triaxial test under unconsolidated-undrained conditions. At failure, the major and minor principal stresses are 8401 psf and 4875 psf, respectively. What is the shear strength of this soil if the confining pressure is doubled? Provide your answer in psf with no decimals.
- A sample of dry sand in relatively loose condi-tion is subject to a triaxial test. The sample failswhen the confining stress (minor principalstress) is 50 kPa and the axial stress (major prin-cipal stress) is 170 kPa. What is the angle ofinternal friction for the soil?The results of a consolidated drained triaxial shear test on a normally consolidated clay are shown in the figure. The angle of internal friction is:--In a tri-axial test of normally consolidated clay, the sample is subjected to chamber of confining pressure of 275 kPa and failed when deviator stress is 375 kPa. 1. Which of the following gives the angle of internal friction? a. 29.32° b. 32.29° c. 22.29° d. 23.92° 2. Which of the following gives the shear stress at failure? a. 187.50 kPa b. 342.79 kPa c. 171.40 kPa d. 205.12 kPa 3. Which of the following gives the effective normal stress at maximum shear? a. 462.50 kPa b. 605.00 kPa c. 512.50 kPa d. 325.00 kPa