A. Freezing Point of Cyclohexane (Solvent) 1. Mass of beaker, test tube (g) 85.364g 2. Freezing point, from cooling curve (°C) 5.68°C B. Freezing Point of Cyclohexane plus Unknown Solute 1. Mass of beaker, test tube, cyclohexane (g) 97.594g 2.* Mass of cyclohexane (g) 3. Tared mass of added solute (g) 0.311g 4. Freezing point, from cooling curve (°C) 1.72°C Calculations 1. ke for cyclohexane (°Ckg/mol) 20.0°C-kg/mol 2. Freezing-point change AT:(°C) 3. Mass of cyclohexane in solution (kg) 4. Moles of solute, total (mol) 5. Mass of solute, total (g) 6. Molar mass of solute (g/mol) Based on your data (the molar of your unknown) what is the likely identity of the solute from the following selection: Naphthalene [C10Hg=128.171g/mol] Aspirin [C,H3O=180.158g/mol] Sucrose [C12H2201=342.3g/mol] Pentanoic acid [C;H19O2=102.13g/mol] 1-Pentanol [C§H120=88.15g/mol] Lactic acid [C3H03=90.08g/mol] 7. Identity of your unknown. Key Equations: ATu: change in the freezing point (°C) n: moles of solute m: molality Uolven' mass of solvent (kg) Molmai Molar of mass of solute ke freezing point depression of solvent i: Van't Hoff factor Uowwi mass of solute (g) ATK = i k,m m=n/mobouh AT = i kelowa/ Mi ATK =| Toow - Tuvw
A. Freezing Point of Cyclohexane (Solvent) 1. Mass of beaker, test tube (g) 85.364g 2. Freezing point, from cooling curve (°C) 5.68°C B. Freezing Point of Cyclohexane plus Unknown Solute 1. Mass of beaker, test tube, cyclohexane (g) 97.594g 2.* Mass of cyclohexane (g) 3. Tared mass of added solute (g) 0.311g 4. Freezing point, from cooling curve (°C) 1.72°C Calculations 1. ke for cyclohexane (°Ckg/mol) 20.0°C-kg/mol 2. Freezing-point change AT:(°C) 3. Mass of cyclohexane in solution (kg) 4. Moles of solute, total (mol) 5. Mass of solute, total (g) 6. Molar mass of solute (g/mol) Based on your data (the molar of your unknown) what is the likely identity of the solute from the following selection: Naphthalene [C10Hg=128.171g/mol] Aspirin [C,H3O=180.158g/mol] Sucrose [C12H2201=342.3g/mol] Pentanoic acid [C;H19O2=102.13g/mol] 1-Pentanol [C§H120=88.15g/mol] Lactic acid [C3H03=90.08g/mol] 7. Identity of your unknown. Key Equations: ATu: change in the freezing point (°C) n: moles of solute m: molality Uolven' mass of solvent (kg) Molmai Molar of mass of solute ke freezing point depression of solvent i: Van't Hoff factor Uowwi mass of solute (g) ATK = i k,m m=n/mobouh AT = i kelowa/ Mi ATK =| Toow - Tuvw
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter12: Solutions
Section: Chapter Questions
Problem 12.98QE
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