a. in a population with allele frequencies that are p=0.44 and q=0.54. How many homozygous recessive individuals would you expect? b. What are the allele frequencies in populations: AA: 14, Aa: 27, aa: 54? c. using the allele frequencies in part b, how many heterozygous individuals would you expect to find in a population of the same size in the next generation?
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- In a population at Hardy-Weinberg equilibrium, 190 out of 1000 individuals have polydactyly. Note that the trait is dominant. a. What is the frequency of the dominant and recessive alleles? b. How many are expected to be heterozygotes for the trait? c. How many are expected to be homozygous dominant?A mouse mutation with incomplete dominance (t =tailless) causes short tails in heterozygotes (t+/t). Thesame mutation acts as a recessive lethal that causeshomozygotes (t/t) to die in utero. In a populationconsisting of 150 mice, 60 are t+/t+ and 90 areheterozygotes.a. What are the allele frequencies in this population?b. Given that there is random mating among mice, nomigration, and no mutation, and ignoring the effects of random genetic drift, what are the expectednumbers of the different genotypes in this nextgeneration if 200 offspring are born?c. Two populations (called Pop 1 and Pop 2) of micecome into contact and interbreed randomly. Thesepopulations initially are composed of the followingnumbers of wild-type (t+/t+) homozygotes andtailless (t+/t) heterozygotes:Pop 1 Pop 2Wild type 16 48Tailless 48 36What are the frequencies of the two genotypes in thenext generation?A population of mice contains 20 animals Show work here: with white tails and 30 animals with grey tails. Grey tails are the dominant trait. a. What is the frequency of the white allele? b. What is the frequency of the grey allele? c. What is the frequency of heterozygotes? d. What is the frequency of mice homozygous for the grey allele?
- Which of the following statements would be true of ahuman trait that has high heritability in a populationof one country?a. The phenotypic difference within monozygotic twinpairs would be about the same as the phenotypic differences among members of dizygotic twin pairs.b. Very little phenotypic variation exists betweenmonozygotic twins but high variability exists between dizygotic twins.c. The trait would have the same heritability in a population of another countryI. A population called the founder generation, consisting of 2000 AA individuals, 2000 Aa individuals, and6000 aa individuals is established on a remote island.Mating within this population occurs at random, thethree genotypes are selectively neutral, and mutationsoccur at a negligible rate.a. What are the frequencies of alleles A and a in thefounder generation?b. Is the founder generation at Hardy-Weinbergequilibrium?c. What is the frequency of the A allele in the secondgeneration (that is, the generation subsequent to thefounder generation)?d. What are the frequencies for the AA, Aa, and aagenotypes in the second generation?e. Is the second generation at Hardy-Weinbergequilibrium?f. What are the frequencies for the AA, Aa, and aagenotypes in the third generation?a.)If the frequency of an allele at a locus of interest is 0.57, what is the frequency of the genotype that is homozygous for this allele (that is, that genotype has two copies of this allele)? b.) If we know that the frequency of an allele at a locus of interest is 0.57, we have enough information to calculate the frequency of the related phenotypes in the population, assuming there are only two alleles.
- Albinism is due to a recessive allele of an autosomal gene. Let a represent the albino allele and A represent the normal non-albino allele. If one out of every 10,000 people were albino and assuming that the population is in Hardy-Weinberg equilibrium, A. what would be the phenotype frequencies of albino and non-albino ? B. what would be the allele frequencies of a and of A? C. what fraction of people can be expected to be of the genotype Aa? D. what fraction of people can be expected to be of the genotype AA?In a large herd of 5468 sheep, 76 animals have yellow fat, and the rest of the members of the herd have white fat. Yellow fat is inherited as a recessive trait. This herd is assumed to be in Hardy-Weinberg equilibrium. A. What are the frequencies of the white and yellow fat alleles in this population? B. Approximately how many sheep with white fat are heterozygous carriers of the yellow allele?°A population of randomly-mating mice contains 35% white mice. The color white is caused by the double recessive genotype, “aa”. Calculate the allelic and genotypic frequencies for this population. °In a flock of chickens, rose comb is dominant over the single comb. Approximately 60% of the chickens in the flock have rose comb, while 40% have a single comb. Determine the expected frequency of: a. q2 b. q c. p d. p2 e. 2pq
- How Can We Measure Allele Frequencies in Populations? Drawing on your newly acquired understanding of the HardyWeinberg equilibrium law, point out why the following statement is erroneous: Because most of the people in Sweden have blond hair and blue eyes, the genes for blond hair and blue eyes must be dominant in that population.How Can We Measure Allele Frequencies in Populations? In a population where the females have the allelic frequencies A = 0.35 and a = 0.65 and the frequencies for males are A = 0.1 and a = 0.9, how many generations will it take to reach HardyWeinberg equilibrium for both the allelic and the genotypic frequencies? Assume random mating and show the allelic and genotypic frequencies for each generation.Imagine that you have a test population of birds. You know from your previous research that there are two alleles (at the same locus) that govern feather type. Genotypes, and their associated phenotypes, are as follows: RR Red feathers Rr Red feathers rr white feathers Observing your population, you determine that you have 500 chickens with white feathers and 600 chickens with Red feathers. Based on Hardy–Weinberg expectations, how many of these are likely to be heterozygotes? (Show all your work)