a. Zero active power b. 6 MW output (total three-phase)
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- 3 X 0.1 1 2 XL = 0.2 to Eato oto O X = 0.1 X = 0.1 Above is the one-line diagram of a simple power system. Each generator is represented by an emf behind the subtransient reactance. All impedances are expressed in per unit on a common base. All resistances and shunt capacitance are neglected. The generators are operating on no load at their rated voltage with their emfs in phase. A symmetrical fault occurs at bus 1 through a fault impedance Z, =j0.08 per unit. a) Using Thevenin's Theorem, determine the impedance to the point of fault and the fault current in per unit. (2 Marks) b) Find the bus voltages and line currents during the fault. (2 Marks)A 100-MVA synchronous generator supplies 62.5 MVA of power at 0.8 lagging power factor. The reactance between the load and the generator is normally 1.0 pu, but it increases to 3.0 pu because of a sudden three-phase short circuit. The fault is subsequently cleared and the generator then supplies 43.75 MVA at 0.8 lagging power factor. Determine the critical clearing angle. Select one: a. 88.58 b. None c. 78.58 d 68.58A power station consists of two synchronous generators A & B of ratings 250 MVA and 500MVA with inertia 1.6 pu and 1.0 pu respectively on their own base MVA ratings. The equivalent pu inertia constant for the system on 100 MVA common base is:- (a) 2.6 (b) 0.615 (c) 1.625 (d) 9.0
- A synchronous generator has been synchronized to an infinite grid of 13.8 kV and 60 Hz. The generator prime mover C/C is such that the no-load frequency is 62.5 Hz and the power slope is 1 MW/Hz. The AVR C/C (The reactive power against the terminal voltage C/C) is such that the zero reactive power voltage is 14.6 kV, while the slope is 0.4 MVAR/kV. Calculate: (a) the kVA loading of the generator and its power factor. (b) the settings of the prime mover and AVR such that the generator delivers 3 MW at 0.85 lagging power factor.In a synchronous generator * the OC voltage leads the terminal voltage by an angle known as power factor angle the OC voltage lags the terminal voltage by an angle known as power factor angle the OC voltage leads the terminal voltage by an angle known as power angle the open-circuit voltage (OC) lags the terminal voltage by an angle known as power angleA parallel connection of a RL branch with a C branch is connected across a 100V AC mains. At first R = 10 ohms, L = 20mH and frequency of 1000rad / s, the current measured is 2.2361A at 89.44 leading power factor. A) Determine the initial capacitance. B) However, a fault occurs on the capacitor branch making its capacitance 20% lower and a resistance of 5 ohms is detected. If this faulty circuit is rerun but at a frequency of 500 rad / s, determine the new current that will flow through the circuit.
- The total reactive power consumed by the three-phase load(in VAr) is??In order to avoid difficulties with third-harmonic exciting current, which three-phase transformer connection is seldom used for step-up transformers between a generator and a transmission line in power systems. (a) Y- (b) -Y (c) Y-YThe total instantaneous power absorbed by a three-phase motor (under balanced steady-state conditions) as well as a balanced three-phase impedance load is (a) A constant (b) A function of time
- A single-phase, 120V(rms),60Hz source supplies power to a series R-L circuit consisting of R=10 and L=40mH. (a) Determine the power factor of the circuit and state whether it is lagging or leading. (b) Determine the real and reactive power absorbed by the load. (c) Calculate the peak magnetic energy Wint stored in the inductor by using the expression Wint=L(Irms)2 and check whether the reactive power Q=Wint is satisfied. (Note: The instantaneous magnetic energy storage fluctuates between zero and the peak energy. This energy must be sent twice each cycle to the load from the source by means of reactive power flows.)Draw a complete equivalent circuit of one phase only of a synchronous generator. Then draw the phasor diagram for a unity power factor. Assume the phase resistance is ignored21) Two 3-phase 6.6kV, Star-connected alternators supply a load of 3000kW at 0.8pf lagging. The synchronous impedance per phase of machine A is (0.5 +j10)Q and machine B is (0.4+j12) Q. The excitation of machine A is adjusted so that it delivers 150A at a lagging pf and the governors are set so that the load is shared equally between the machines. Find the line to line voltage of alternator B.