a. ~ [(~PVQ)V~ (ΡΛQ)] b. [(PV (P ΛQ)] → P
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- Let L = {w = [a, b}*: every a in w is immediately followed by at least one b}.Let A = {a, b, c} and B = {u, v}. Write a. A × B b. B × Afunction [P, A] = rect(L, W) P= 2 (L+ W); A =L*W; end Above function is defined to find perimeter and area of a rectangle. If a rectangle has length 10 mm and width 7 mm then the correct way to get perimeter and area of a given rectangle by executing this function is Select one: a. [A, B] = rect(10, 7) b. rect(7, 10) c. [A, B] = rect(7, 10) d. rect(10, 7)
- le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"] ] is_bipartite In the cell below, you are to write a function "is_bipartite (graph)" that takes in a graph as its input, and then determines whether or not the graph is bipartite. In other words, it returns True if it is, and False if it is not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (is_bipartite({"A" : ["B", "C"], "B" : ["A"], "C" : ["A"]}), is_bipartite({"A" : ["B", "C"], "B" : ["A", "C"], "C" : ["A", "B"]})) This should return True False Python PythonB=(1)/(4)e*p slove for e
- ] ] is_proper You are to write a function is_proper(graph,color) that has two inputs: one a graph, and the other a labelling of the vertices, and determines whether or not the labelling is a proper vertex-coloring of the given graph. In other words, return the Boolean value True if it is, and False if it is not. After compiling the above cell, you should be able to compile the following cell and obtain the desired outputs. print (is_proper({"A": ["B", "C"], "B": ["A", "C"], "C": ["A", "B"]}, {"A": 1, "B": 2, "C": 3}), is_proper({"A": ["B", "C"], "B": ["A", "C"], "C": ["A", "B"]}, {"A": 1, "B": 1, "C": 3})) This should return True False Python Pythondef strPattern(mystr):lenght = len(mystr)mystr1 = ""for i in range(lenght - 1):mystr1 = mystr1 + mystr[i].upper() + str(i + 1)if lenght == 0:return mystr1return mystr1 + mystr[-1].upper()s = input("enter a word: ")print(strPattern(s)) s = input("enter a word: ") EOFError: EOF when reading a line HOW CAN I FIX THIS QUESTION?c) [a] = [a] for all a e R. True or False? Give a counterexample if false. d) [a] = [a] 1 for all a eR - Z. True or False? Give a counterexample if false. e) Is 80 congruent to 5 modulo 17? Why, or why not?
- [Unbalanced Rod] Given a set of n weights {w₁,..., wn} and a rod of length n - 1 inches, we can attach the weights to the rod at hooks placed at one inch distances apart as shown in the figure below. -1". /10 2 3 12 2 4 We can attach a weight to any hook but no two weights can be attached to the same hook and we have to attach all the weights. For any given assignment of weights to hooks, we can compute the location of the center of mass of the rod and the weights according to the following equation (neglecting the weights of the rod and the hooks). where 0 ≤ Pi≤n-1 is the position of weight along the rod. For example, in the figure shown above, the center of mass is computed as C= C = i Wi Pi Σi Wi 10 0+2 1+3·2+4·3+12.4 +2.5 10+2+3+4+12+2 78 33 The problem is to find an assignment of weights to hooks that makes the center of mass as far as possible to the left, i.e., minimize the value of c. Answer the following questions. 1. Describe a greedy algorithm that finds the assignments that…Q3: Superheroes Supervillains are tired of Toronto condo rental prices, so they are leaving Toronto for Mississauga. Luckily, we have valiant superheroes that can deal with them. The superhero () has a name , an intelligence score , and a strength score .ni-th0 = gin[x] + s[x] Detective Zingaro has asked for your help. For each of the supervillains, tell him the name of the superhero that should deal with that supervillain. Note: A superhero can be assigned to multiple supervillains (or none at all). Note: whenever there are multiple superheroes that satisfy the given requirements for a supervillain, report the one whose name is lexicographically smallest (i.e. the one that’s the smallest according to Python’s ordering of strings). It’s guaranteed that superheroes have distinct names. Hint: Tuples of multiple elements may be helpful here. In python, you can compare two tuples and . If and are different, the result is the same as comparing and . If and are equal, the result is the same…Ex: Let A1 ={x, y}, A2 ={1, 2}, and A3 ={a, b}, Find A1 × A2, (A1 × A2) × A3, A1 × A2 × A3.