Addison's disease is a thyroid condition in dogs. It is more prevalent in bearded collies than other breeds. Although genetic inheritance for this disorder is uncertain, let's assume for this question that it is an autosomal recessive disorder. Part 1 If the recessive allele that causes Addison's disease is present at a frequency of 0.15, how many dogs in a breeding colony of 100 dogs would you expect to have Addison's? Assume Hardy Weinberg equilibrium. 2 4 30 15

Addison's disease is a thyroid condition in dogs. It is more prevalent in bearded collies than other breeds. Although genetic inheritance for this disorder is uncertain, let's assume for this question that it is an autosomal recessive disorder. Part 1 If the recessive allele that causes Addison's disease is present at a frequency of 0.15, how many dogs in a breeding colony of 100 dogs would you expect to have Addison's? Assume Hardy Weinberg equilibrium. 2 4 30 15

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

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Tay-Sachs disease is caused by loss of function mutation in a gene on chromosome 15 that codes for an enzyme. The disease is an inherited autosomal recessive condition which is found amongst Ashkenazi Jews of Central European origin. In this population, 2 in 4,900 children are born with the disease. What proportion of the population are carriers (heterozygotes) for this disease? ALL WORKING MUST BE SHOWN
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True-breeding diabetes-resistant male monkeys were bred to true-breeding wildtype female monkeys. All the F1 monkeys are phenotypically wildtype. The F1 monkeys are bred to each other, producing eight F2 babies. Only one of the eight F2 monkeys has the diabetes resistance. Is it possible for this condition to be controlled by a single autosomal gene? Use chi-square analysis to test the hypothesis, show your work, and explain your conclusion.
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A recessive maternal effect mutant in zebrafish, called ichabod, results in embryos lacking heads that are non-viable. You have been instructed to identify females that are homozygous for the ichabod mutant allele. At your disposal are a tank of wild-type fish (males and females), a tank of male and female parental fish that are all heterozygous for the ichabod mutant allele (ichabod/+), and a tank of F1 fish derived from a cross between a heterozygous male and heterozygous female (ichabod/+). Which of the following would be a way to identify females that are homozygous mutant, i.e. ichabod/ichabod? Select all answers that would work.
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