All the necessary values have been found to find the 95% confidence interval. We have x = 832, Za/2 = 1.960, o = 150, and n = 100. Find the lower bound of the confidence interval, rounding the result to the nearest integer. X-E = X-²a/2 = 832 - x+E=x+Za/2 Find the upper bound of the confidence interval, rounding the result to the nearest integer. of 0 = 832 + /100 O √n 150 V100 Therefore, rounded to the nearest integer, a 95% confidence interval for the population mean examination score is from a lower bound to an upper bound of

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