Aluminum hydroxide dissolves in strong acid by the following reaction. Al(OH)3(s) + 3 H3O+(aq)  Al3+ (aq) + 6 H2O(l) (a) What is the equilibrium constant expression for the reaction?  (b) Use the following equilibrium constants to calculate the value of K for the above reaction. H3O+(aq) + OH −(aq)  2 H2O(l) K1 = 5.6  x1015 Al(OH)3(s)  Al3+(aq) + 3 OH −(aq) K2 = 1.9  x10-33

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