AMPAD A 67°17 ل P THE FOUR SIDED CLOSED TRAVERSE HAS THE FOLLOWING ANGLES & DISTANCES. A 51°23' B 105°39' C 78° 11' AB=713.93 FT. BC= 606.06 FT. CD = 391.27 FT. D 124°47 DA = 781.18 FT THE AZIMUTH OF AB 15 67° 17'. UTILIZING THE INFORMATION FROM THE TRAVERSE HOMEWORK ASSIGNMENT I 1. COMPUTE THE LATITUDES & DEPARTURES (24POINTS) 2.COMPUTE THE LINEAR MIS-CLOSURE (GPOINTS *DO NOT ADJUST THE LATITUDES & DEPARTURES AFTER COMPUTING THE LINEAR MIS-CLOSLIRE

V;19 | ZAO N O o GOX U | KOREK Traverse_ho... 0:- The table below shows the ficld measurements for a traverse A, B.C. D, E, if the Azimuth of AB = 290" and the coordinate of point A (1000, 1000) . Calculate the coordinates of all stations of the traverse. Point Line Length(m) Azimuth Angle to the right A AB 50 290 B 90 BC 65 95 CD 61 D 120 DE 50 E A

LINE LENGTH IN METERS BEARING AB 82.62 S60°43'E BC 111.41 N52°41'W CD 100.66 S71°43'W DE 62.97 N75°44'W EA 181.24 S85°23'E Using TRANSIT RULE, complete the table of balancing the traverse. -Retain 3 decimal places.

ANSWER KEY=D 108.1502m∆h 22.4596m

Deflection Angle Traverse Given the bearing of each line of a closed traverse ABCDEF, determine the deflection angles of each line.   Line Bearing AB S 46°17’ E BC N 23°28’ E CD N 78°55’ W DE S 56°42’ W EF S 13°00’ W FA N 76°05’ E   * Sum of Deflection Angle = 360° * Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.   (Please answer this problem with accurate and proven solution. Thank u)

PROBLEM 1. Given in the accompanying tabulation are the adjusted latitude and adjusted departure of a closed traverse. Calculate the area by the DMD method LINE ADJ ADJ LAT DEP AB - 125.055 + 196.387 BC +20.241 + 241.003 CD +180.107 + 65.326 DE +210.169 - 104.519 EF -74.003 - 260.516 FA - 211.459 - 137.681

Bearing Angle Traverse Given the tabulated measurement of a closed traverse with unknown length and bearing of line EA, determine the following: The Latitude and Departure of each Line.  The Length of Line EA.  The Bearing of Line EA.  Plot the Traverse.  Line Length Bearing AB 585.730 m S 47°10’ E BC 496.080 m N 65°38’ E CD 999.900 m S 79°52’ E DE 795.340 m N 55°25’ E EA Unknown Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.   Note: Please be accurate in providing solution. Thank you so much.

: Determine the graph and conversion of the following angles.1. Convert the following azimuth 190º15.40'45” to heading.2. Graphic 66º7´9”3. Convert the following heading S 74º9'30” W to azimuth.4. Convert the following azimuth 200º46´7.12” to heading.5. Graph 245º52´14”

PROBLEM 17: The following are bearings and distances taken on a closed traverse. Bearing N60°E Line Distances АВ 1000 m ВС Due South N60°W A line from vertex A to point F on the side BC divides the area and makes area ABF to be 280 000 m?. Find the length of the line AF. CA a. 878.35 m b. 750,12 m c. 646.63 m d. 593.30 m

Bearing Angle Traverse Given the tabulated measurement of the closed traverse as shown. Determine the area of the traverse using DPD Method. Line Length Bearing AB 413.600 m N 09°30’ W BC 304.380 m N 55°06’ W CD 407.210 m S 57°35’ W DE Unknown S 04°05’ E EA 649.630 m Unknown Note: EXPRESS YOUR ANSWER UPTO 3 DECIMAL PLACES.