- 4 +8- 212 = 0An application of Kirchhoffs Rules to thecircuit shown results in the followingsystem of equations.6 24 V8 = 814 +1112Find the currents I,, 12. 13. 14.4 = 613 +1%3113 + l4 = 1Select the correct choice below and fill in any answer boxes within your choice.O A. The currents are l, =13and I4 =(Simplify your answers.)B. There is no possible combination of currents that satisfy the circuit.

Given Data : The system of equations are given as -4+8-2I2=08I4+I1=86I3+I1=4I3+I4=I1

An application of Kirchhoff's Rules to the 4 +8- 212 = 0 6 2 circuit shown results in the following system of equations. 8 = 814 +11 12 222 4 = 613 +11 I3 + l4 = 11 Find the currents I,. 12. 13. 14- Select the correct choice below and fill in any answer boxes within your choice. O A. The currents are l, = 13 = and l4 = (Simplify your answers.) B. There is no possible combination of currents that satisfy the circuit. a a

An application of Kirchhoff's Rules to the 4 +8- 212 = 0 6 2 circuit shown results in the following system of equations. 8 = 814 +11 12 222 4 = 613 +11 I3 + l4 = 11 Find the currents I,. 12. 13. 14- Select the correct choice below and fill in any answer boxes within your choice. O A. The currents are l, = 13 = and l4 = (Simplify your answers.) B. There is no possible combination of currents that satisfy the circuit. a a

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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