An electrical motor spins at a constant 2857. rev/min. If the armature radius is 2.685 cm, what is the acceleration of the outer edge of the armature? O O O O O2403 m/s² O 241,100 m/s² 844.4 m/s² O 84.40 m/s²

An electrical motor spins at a constant 2857. rev/min. If the armature radius is 2.685 cm, what is the acceleration of the outer edge of the armature? O O O O O2403 m/s² O 241,100 m/s² 844.4 m/s² O 84.40 m/s²

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter2: Motion

Section2.3: Acceleration

Problem 2.3CE: What is the average speed in mi/h of a person at the equator as a result of the Earths rotation?...

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Concept explainers

Centripetal Force

A particle, body, object or certain mass while travelling in a rotational path or semicircular path, experiences an inertia force. If that inertia force pulls the towards the inward of the imaginary circle in the rotation, it is termed as centripetal force.

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Part A
An electrical motor spins at a constant 2857.0 rev/min. If the armature radius is 2.685 cm, what is the acceleration of the outer edge of the armature?
O 2403 m/s²
O 241.100 m/s²
O 844.4 m/s²
O 84.40 m/s²

Expert Solution

Step 1

Given,

Electrical motor spins at = 2857 rpm.

Radius = 2.685 cm.

We need to calculate,

Acceleration of the outer edge of motor =?

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