An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ = after Qf= pC pC (b) Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV₁ = (c) Determine the change in energy (in nJ) of the capacitor. AU = (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q; = pC pC after QF = Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV₁ = Determine the change in energy (in nJ) of the capacitor. AU = n]
An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ = after Qf= pC pC (b) Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV₁ = (c) Determine the change in energy (in nJ) of the capacitor. AU = (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q; = pC pC after QF = Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV₁ = Determine the change in energy (in nJ) of the capacitor. AU = n]
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Capacitance And Dielectrics
Section: Chapter Questions
Problem 26.12OQ: (i) Rank the following five capacitors from greatest to smallest capacitance, noting any cases of...
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![An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the
battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.
(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Q₁
after Qf =
=
(b) Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf =
AV f =
F
V
pC
pC
(c) Determine the change in energy (in nJ) of the capacitor.
AU =
nJ
(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference.
Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Q₁
pC
pC
after Qf =
Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf
AV f =
F
V
Determine the change in energy (in nJ) of the capacitor.
AU = |
n]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F76aaab3c-5a4a-4ff8-814d-d2e8a1f30217%2F06cc8366-feba-4e77-aed1-37fc77287617%2Flnxy66r_processed.png&w=3840&q=75)
Transcribed Image Text:An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the
battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0.
(a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Q₁
after Qf =
=
(b) Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf =
AV f =
F
V
pC
pC
(c) Determine the change in energy (in nJ) of the capacitor.
AU =
nJ
(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference.
Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.)
before Q₁
pC
pC
after Qf =
Determine the capacitance (in F) and potential difference (in V) after immersion.
Cf
AV f =
F
V
Determine the change in energy (in nJ) of the capacitor.
AU = |
n]
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