An object revolves around the Earth in a circular orbit whose radius is five times that of the radius of the Earth. The gravitational field strength at the surface of the Earth is 9.8 N kg'. Determine the period of revolution of the object. 2. (a) (b) Calculate the gain in potential energy of a satellite of mass 3000 kg between its launch and when it is at a height of 0.12 × 106 m above the Earth's surface. [Mass of Earth = 5.98 × 1024 kg Radius of Earth = 6.37 × 106 m Gravitational constant, G = 6.67 x 101" N m? kg²] %3D

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Chapter13: Universal Gravitation
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An object revolves around the Earth in a circular orbit whose radius is five times
that of the radius of the Earth. The gravitational field strength at the surface of the
Earth is 9.8 N kg'. Determine the period of revolution of the object.
2.
(a)
(b) Calculate the gain in potential energy of a satellite of mass 3000 kg between its
launch and when it is at a height of 0.12 × 106 m above the Earth's surface.
[Mass of Earth = 5.98 × 1024 kg
Radius of Earth = 6.37 × 106 m
Gravitational constant, G = 6.67 x 101" N m? kg²]
%3D
Transcribed Image Text:An object revolves around the Earth in a circular orbit whose radius is five times that of the radius of the Earth. The gravitational field strength at the surface of the Earth is 9.8 N kg'. Determine the period of revolution of the object. 2. (a) (b) Calculate the gain in potential energy of a satellite of mass 3000 kg between its launch and when it is at a height of 0.12 × 106 m above the Earth's surface. [Mass of Earth = 5.98 × 1024 kg Radius of Earth = 6.37 × 106 m Gravitational constant, G = 6.67 x 101" N m? kg²] %3D
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