An unstiffened web I-section is fabricated from a 10 mm thick plate by fillet welding as shown in the figure. If yield stress of steel is 250 MPa, the maximum shear load that section can [2 Marks] take is 10 mm 300 mm 10 mm 200 mm
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Q: A hollow section bar has an outside diameter of 120 mm and an inside diameter of 60 mm. If the shear…
A: Ro = Outside radius = 1202 = 60 mmRi = Inside radius = 602 = 30 mmζy = Shear stress at yield = 100…
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Q: The wooden beam shown is made by gluing together planks as shown. 8 kN/m Glue 80 mm 80 mm - NA 6 m…
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Q: wla V sI Untitled A rod is composed of an aluminum section rigidly attached between steel and bronze…
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Q: A steel rod with a cross sectional area of 120〖mm〗^2 is stretched between two fixed points. The…
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Q: 1. A hollow bronze shaft of 3 in. outer diameter and 2 in. inner diameter is slipped over..a solid…
A: (NOTE:Since you have asked multiple question, we will solve the first question for you. If you want…
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A: Diameter of bar = 0.70 Inch Load at proportional limit = 5400 lb Gauge length of bar = 2.20 inch…
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A: Given: Diameter of rod, d = 10 mm Shear modulus = 80 GPa Angle of twist = 90° Allowable shear stress…
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Q: A 31 mm radius Steel is subjected to tensile test. Determine its yield and ultimate load it can…
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Q: A 5 cm diameter shaft is reduced to a diameter of 2.5 cm and subjected to a torque of 200 N-m. It is…
A: Solution: Given Data: Diameter of the shaft, D= cmChange in diameter, δd=2.5 cmTorque, T=200…
Q: 3. A bronze bar is fastened between a steel bar and an aluminum bar as shown in Fig. P211. Axial…
A: We have to determine the value of largest value of P that will not exceed an overall deformation of…
Q: steel A- 325 mm E- 200 MPa N 2m Aluminum A- 485 mn %3D E: 69 MPa
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Q: A tensile test was conducted on a mild steel bar. The following data was obtained from the test:…
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Q: A high-strength steel band saw, 22 mm wide, runs over pulleys 800 mm in diameter. What minimum…
A: Given data: Width=22 mm Diameter of pulley=800 mm E==230 Gpa Flexural stress=350 It is asked to…
Q: An unstiffened web l-section is fabricated from a 10 mm thick plate by fillet welding as shown in…
A: Given, Thickness of the plate= 10mm Web depth = 300-20= 280mm Yield stress (fy) = 250mpa fs= 0.4fy =…
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Q: At fracture, the elongation between the gape marks is 0.12 in. and the minimum diameter is 0.42 in.…
A: limit of proportionality = 59.91 psi modulus of elasticity E =30046 psi yield stress = 68.897 psi…
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A: To Find :- Maximum shear stress Angle of twist per unit length
Q: As shown in the figure below, a bronze bar is affixed between a steel bar and an aluminum bar. Axial…
A: Given, Allowable stress :- σst = 150MPa σbr= 130MPa σal = 90MPa Est= 200Gpa Eal= 70Gpa Ebr= 83Gpa
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A: Given : Unsymmetrical I section and hollow rectangular section are given. Plastic and elastic…
Q: 5. A bronze bar is fastened between a steel bar and an aluminum bar as shown in the given figure.…
A: Steel section - P = σstAst⇒P = 120×480⇒P =57600 N Bronze section - Pbr = σbrAbr⇒2P = 90×650⇒2P…
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Q: The composite shaft shown in the figure consists of a bronze sleeve (1) securely bonded to an inner…
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Q: Two plates are bonded together by glue as shown. If P = 60 kN and the allowable shear stress of the…
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Q: A plate of 150 mm width and 20 mm thick is welded to another plate by fillet weld as shown in the…
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Q: The lapbelt assembly is to be subjected to a force of 800 N. 800 N 5 mm SO0 N What is the required…
A: Given data, Force = 800N Allowable shear stress = 0.74MPa To find the required lap length d1.
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Q: iš testéd to specimen of steel 20 mm diameter with a gauge length destruction. It has an extension…
A: Given:- d = 20mm L = 200 mm dl=0.25 mm P=80kN=80 *103 N Elastic Limit = 102 kN = 102 * 103 N Maximum…
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Q: H.W 3 Two aluminum alloy plates (2) are attached to the sides of a wooden beam (1) as shown in…
A: The given data is: Mz=600 Nm E1=12.5 GPa E2=70 GPa The modular ratio will be: n=E2/E1=70/12.5=5.6
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- The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.The light rigid bar ABCD shown is pinned at C and connected to two vertical rods. The bar was initially horizontal, and the rods were stress-free before the load P = 20 KN is applied. %3D Steel E200 GPa A-600mm L1 m 2.0 m 0.6 m 1.5 m Pa20 KN Aluminum E-70 GPa A=900mm L-1.5 m What is the ratio of the deformation of steel to deformation of aluminum?PROBLEM 1) An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m D 10KN 0.8m 0.4m B 5KN 0.6m AL 20KN What is the deformation &pE in mm? A=800 mm² A=1,200 mm²
- 1.12 A fillet-welded joint of 6 mm size is shown in the figure. The welded surfaces meet at 60-90 degree and permissible stress in the fillet weld is 108 MPa. The safe load that can be transmitted by the joint is 100 mm F F 810 50mmThe following steel member is connected to the gusset plate via two longitudinal welds. The width of the member is 58 mm and the length of the weld is 87 mm. The yield stress is 300 MPa and the ultimate stress is 675 MPa. The gross area of the member is 700 mm^2 . a. What is the tensile design yield strength in KN? b. What is the tensile design rupture strength in KN? c. If a tensile load of 85 KN is requiredfor the member, what is the minimum factor of safety for the steel member?A plate of 150 mm width and 20 mm thick is welded to another plate by fillet weld as shown in figure below. The size of the weld is 12 mm throughout. Compute the average shear stress produced in the weld for the full strength of the plate if the allowable stress is 150 N/mm². 70.72 mm T 50 mm 1 ㅅ 70.72 mm 150 mm- -150 mm -60 mm dia T 150 mm
- An aluminum bar carries the axial loads at the positions shown. If E=70GPA, compute the total deformation of the bar. Assume that the bar is suitably braced to prevent buckling. 0.4m 10KN 0.8m 0.4m 5KN 0.6m What is the deformation 8Rc in mm? Al 20KN A=800 mm? A=1,200 mm²Situation No. 2 A bronze bar is fastened between a steel bar and an aluminum bar as shown below. Axial loads are applied at the positions indicated. Find the largest value of P that will not exceed an overall deformation of 3.0 mm, or the following stresses: 140 MPa in the steel, 120 MPa in the bronze, and 80 MPa in the aluminum. Assume that the assembly is suitably braced to prevent buckling. Use Est = 200 GPa, Eal = 70 GPa, and Ebr = 83 GPa. Bronze Steel A = 480 mm? Aluminum A = 650 mm A = 320 mm 3P 4P 2P 1.0 m 2.0 m 1.5 mThe 200-mm square aluminum block supports a compressive load of 300 kN. What is the normal stress acting on section a–a in MPa What is the shearing stress acting on section a–a in MPa The lapbelt assembly is to be subjected to a force of 800 N. What is the required thickness t in mm. of the belt if the allowable tensile stress for the material is 10 MPa?
- The 10-mm-diameter steel bolt is surrounded by a bronze sleeve. The outer diameter of this sleeve is 20 mm, and its inner diameter is 10 mm. If the yield stress for the steel is (ay) MPa, and for the bronze (ay)or 520 MPa, determine the magnitude of the largest elastic load P 640 that can be applied to the assembly. E 200 GPa, Ebr= 100 GPa. 10 mm 20 mm Figure 2: Steel BoltA compressive load P is transmitted througha rigid plate to three magnesium-alloy bars that areidentical except that initially the middle bar is slightlyshorter than the other bars (see figure). The dimensionsand properties of the assembly are as follows:length L = 1.0 m, cross-sectional area of each barA = 3000mm2, modulus of elasticity E = 45 GPa,and the gap s = 1.0 mm.(a) Calculate the load P1 required to close the gap.(b) Calculate the downward displacement d of therigid plate when P = 400 kN.(c) Calculate the total strain energy U of the threebars when P = 400 kN.(d) Explain why the strain energy U is not equal toPδ / 2. Hint: Draw a load-displacement diagram.Maxinnun allowable stress for steel - 140 MPa Maxinnum allowable stress for ahuminum = 90 MPa Maxinnun allowable stress for brouze - 100 MPa Required: Maximun safe value of axial load P Aluminum A 400 mm Bronze A= 200 mm Steel A= 500 mm 2P 4P 2.5 m 2.0 m 1.5m