Answers: FA= FB = i i kN kN
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- Replace the two cable tensions which act on the pulley at O of the beam trolley by two parallel forces which act at pulley connections A and B. The forces are positive if up, negative if down. 200 mm 160 mm 8.3 KN 200 mm BO /B 4.8 KNQ.2. Force P is acting in the negative y-direction and has a magnitude of 120 N, and force Q is acting in the negative z-direction and has a magnitude of 225 N. Given this loading, solve for the forces in members AB, BC, EC, ED and AD. A 0.6 m 3 m B 0.6 m 2.25 m 1.2 m 0.75 mQ.4) Force P is acting in the negative y-direction and has a magnitude of 200 N, and force Q is acting in the negative z-direction and has a magnitude of 300 N. Given this loading, solve for the forces in members DA, DC, DE, and AE. 0.6 m 3 m B 1.2 m y C A E 0.75 m 0.6 m D 2.25 m x
- Replace the system of forces acting on the frame as shown by a resultant R at A and a couple acting horizontally through B and C. Force on top 10 kN, bottom left is 40 kN, and bottom right is 50 kN. 1m A 3 m 2 m 4 m OR= 20KN, B = 95KN, C= -95KN OR- -20KN, B = -95kN, C = 95KN OR= 20KN, B = -95KN, C = 95kN OR=-20KN, B = 95KN, C = -95kN mathalino,comQ2:In the design of the lifting hook the action of the applied force F at the critical section of the hook is a direct pull at B and a couple. If the magnitude of the couple is 40 lb-ft, determine the magnitude of FQ2/ Determine the magnitude of the moment of force F about segment OA .of the pipe assembly as shown in Figure Joli 5 0.5 m F= 300 N B 0.5 m 0.3 m. 0.4 m <0.1 m y 0.2 m
- Q2: Replace the three forces acting on the gear by an equivalent system consisting of a force at O and couple 2.4 kN 202 15 kN 120mim 200 mm 300 mm 3.6 kNDetermine the internal forces at point J when a= = 0.The link shown is subjected to two forces F1 and F2. ... Determine the magnitude and direction of the resultant force. ... F = 750 N F = 300 N F = 400 N 30° 50°
- The link shown is subjected to two forces F1 and F2 f3. ... Determine the magnitude and direction of the resultant force. ... F = 750 N F = 300 N f = 400 45° 30°4. A machine component is subjected to the forces and couples as shown. If P = 60 N, determine the magnitude and direction of the resultant force as well as the location where the resultant force passes through vertical line GF and horizontal line GH. 15 200 N 50 mm 520 mm E 50 mm 240 mm 42 N-m D 120 N 70⁰ 40 N-m 640 mm H 80 N 180 mm B +50mm Ans: (a) 0.365 m above G (b) 0.227 m to the right of GThe horizontal top of a concrete column is subjected to the system of forces shown. Represent the resultant of all forces as a force R at point O and a couple M. Also specify the magnitudes of R and M. 5 kN 0.5 m 3 kN 0.5 m 3 kN 0.5 m 2 kN 0.2 m 3 kN 1 kN 1 kN 2 kN Fozm 0.2 m 0.2 m Answers: R = ( i i+ i j+ i k) kN M = ( i i+ i j+ i k) kN-m R = i kN M = kN.m