Apply the trigonometric substitution x = √3 sec(0). When determining the lower limit, you will have two possible choices for 0. Pick the value of that has its terminal side in the quadrant that ensures √x² - 3 will be positive. -√3 6x²-3 dx = X 6√3 sec²(0) - 3 √3 sec(0) X X ) de

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.3: Trigonometric Functions Of Real Numbers
Problem 32E
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Apply the trigonometric substitution x = √3 sec(0). When determining the lower limit, you will have two possible choices for 0. Pick the value of that has its terminal side in the quadrant that ensures
x² - 3 will be positive.
[-√³6√x²-3 dx = 1²
X
-2
X
X
6√3 sec²(0) - 3
√3 sec(0)
de
X
) de
Transcribed Image Text:Apply the trigonometric substitution x = √3 sec(0). When determining the lower limit, you will have two possible choices for 0. Pick the value of that has its terminal side in the quadrant that ensures x² - 3 will be positive. [-√³6√x²-3 dx = 1² X -2 X X 6√3 sec²(0) - 3 √3 sec(0) de X ) de
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