Around 2.5 centuries ago, several physicists of the time came up with the notion of a dark star. This was a star so dense, with so much gravity, that not even light could escape. The calculations used Newtonian mechanics. In class, we calculated the escape speed from the surface of the earth or the distance from the sun, and the mass of the planet or star. Here, the process is partially reversed. Calculate the dark star radius from the mass of the star and the escape speed. Answer in kilometers. • c = 3*108 m/s M = 3.7*1030 kg G = 2/3 * 10-10 N*m?/kg²

Around 2.5 centuries ago, several physicists of the time came up with the notion of a dark star. This was a star so dense, with so much gravity, that not even light could escape. The calculations used Newtonian mechanics. In class, we calculated the escape speed from the surface of the earth or the distance from the sun, and the mass of the planet or star. Here, the process is partially reversed. Calculate the dark star radius from the mass of the star and the escape speed. Answer in kilometers. • c = 3108 m/s M = 3.71030 kg G = 2/3 * 10-10 N*m?/kg²

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter13: Gravitation

Section: Chapter Questions

Problem 59AP: A neutron star is a cold, collapsed star with nuclear density. A particular neutron star has a mass...

See similar textbooks

Similar questions

Since 1995, hundreds of extrasolar planets have been discovered. There is the exciting possibility that there is life on one or more of these planets. To support life similar to that on the Earth, the planet must have liquid water. For an Earth-like planet orbiting a star like the Sun, this requirement means that the planet must be within a habitable zone of 0.9 AU to 1.4 AU from the star. The semimajor axis of an extrasolar planet is inferred from its period. What range in periods corresponds to the habitable zone for an Earth-like Planet orbiting a Sun-like star?
What would be the Schwarzschild radius, in light years, if our Milky Way galaxy of 100 billion stars collapsed into a black hole? Compare this to our distance from the center, about 13,000 light years.
What is the Schwarzschild radius (in km) of a 6Msun black hole? What fraction of the Earth's radius is this? What percent of the speed of light (2.998 x 108 m/s) is the escape velocity at the Schwarzschild radius? Part 1 of 3 The Schwarzschild radius of a black hole is given by: 2GM Rs = c2 so for the given mass, 2G(6)(Msun) Rs c2 where M. Sun = 1.99 x 1030 kg. Then convert this into kilometers using 1 km = 1,000 m. Rs km
Can you please help w/ the question in the pic? This is the data I have so far: 1. Determine the mass M of the massive object at the center of the Milky Way galaxy. Take the distance of one light year to be 9.461x10^15: answer= 4.26*10^37 2.Express your answer in solar masses instead of kilograms, where one solar mass is equal to the mass of the sun, which is 1.99*10^30: answer=2.14*10^7 TIA
Many galaxies appear to have supermassive black holes in their centers powering active galactic nuclei (also called AGN). The Schwarzschild radius of these supermassive black holes can be estimated in part by watching for changes in the brightness of the surrounding AGN and measuring the timescale of those changes. Assume we observe an AGN and determine it varies with a timescale of 9.85 minutes, which implies a Schwarzschild radius on the order of 1.77x1011 meters. Estimate the mass of this supermassive black hole. kg
he Sun’s mass is 2.0×1030kg, its radius is 7.0×105km, and it has a rotational period of approximately 28 days. If the Sun should collapse into a white dwarf of radius 3.5×103km,, what would its period be if no mass were ejected and a sphere of uniform density can model the Sun both before and after
The Small Magellanic Cloud is a dwarf galay orbiting the Milky Way at a distance of 50 kiloparsecs from its center, on a circular orbit. It is moving at a velocity. rolative to the Milky Way, of 207 km/s. What is the mass of the Milky Way, in units of solar masses, inside the Cloud's orbit? B !! 245 If'a quasar emits 10^(10) times the Sun's luminosity, converting 10% of the mass of the material it eats into radiation, how many stars (ach of the Sun's mans) must it consume per year?
(Astronomy) Neutron Star, White Dwarf Binary Separation. A neutron star and a white dwarf have been found orbiting each other with a period of 42 minutes. What is their average separation? Compare the separation with the radius of the Sun, 7×105 km. A typical white dwarf is about as massive as the Sun. Suppose the mass of the neutron star is 2 solar mass. (Hints: Use the version of Kepler's third law for binary stars and make sure you express quantities in units of AU, solar masses, and years.)
We know that we can use Kepler's Laws to determine the orbits objects around one another. We also have learned that most stars orbit at least one other star (two stars orbiting each other is called a binary system). With this in mind, let's figure out the total mass of both stars of a binary system. Observing the spectra of the two stars orbiting one another, we determine the orbital period of this set of example stars around the system's center of mass to be 0.25 years (1/4 of a year) and the separation of the two stars to be 0.75 AU (3/4 of an AU). With this information, what is the sum of the mass of these two example stars orbiting each other?
what is the answer for sub-item (b) if the radius of the neutron star is 6.676 km? (express your answer in the proper SI unit and without scientific notation) (b)What is the average density of a neuron star that has the same mass as the sun but a radius of only 20.0 km?
When you throw a ball into the air, it usually falls back down. If you throw it a little harder, it will take it longer to fall back down. You can throw it so hard that it never falls back down to Earth. This launch speed is called the escape velocity. When you are far from Earth, the potential energy of an object with mass m can no longer be written as PE = mgh. Instead, we must use the equation М-т PE = -G .. 1" M is the mass of the planet you launch from. m is the mass of the object being launched. r is the distance from the center of the planet to the object being launched. G is a universal constant called the gravitational constant (6.67-10-" ). kg-s Notice that the potential energy is 0 when you are infinitely far away from the planet, and negative as you get closer.
(Astronomy) PSR1913+16 Problem III. As the shape of the graph shown is not skewed, the orbit can be assumed circular. Also assume the system is viewed edge-on (that is, the orbital system is not inclined to the observer). Using these assumptions, the maximum radial velocities, and the orbital period T = 7.75 hours, find the orbital radii of the stars from the center of mass. (Hints: The figures below may be helpful. Use v = 2πr/P, where v is velocity, P is period, and r is radius. Note: redshifts have positive radial velocities values in the upper figure, whereas blueshifts have negative radial velocity values.)