As the following UML diagram illustrates, an aggregation association appears as a solid line with an unfilled diamond at the association end, which is connected to the whole that represents the aggregate, implement the UML diagram. inside the CylenderTest class first create a Circle object then use it to create a Cylinder object, after that print out the volume and area of the Cylinder. Area of a circle A = πr²

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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As the following UML diagram illustrates, an aggregation association appears as a solid line with an unfilled diamond at the association end, which is connected to the whole that represents the aggregate, implement the UML diagram. inside the CylenderTest class first create a Circle object then use it to create a Cylinder object, after that print out the volume and area of the Cylinder. Area of a circle A = πr²

As the following UML diagram illustrates, an aggregation association appears as a solid line
with an unfilled diamond at the association end, which is connected to the whole that
represents the aggregate, implement the UML diagram. inside the CylenderTest class first
create a Circle object then use it to create a Cylinder object, after that print out the volume
and area of the Cylinder. Area of a circle = A = T r²
Transcribed Image Text:As the following UML diagram illustrates, an aggregation association appears as a solid line with an unfilled diamond at the association end, which is connected to the whole that represents the aggregate, implement the UML diagram. inside the CylenderTest class first create a Circle object then use it to create a Cylinder object, after that print out the volume and area of the Cylinder. Area of a circle = A = T r²
11:16
E 19%!
Circumference of a circle = C = 2r
Volume of a cylinder=V=r*h
Area of a cylinder A = 2arh+2r?
CylinderTest
Cylinder
-height: double
-sircle : Circle
+ maino
+Cylinder(h: double, c: Circle)
+findVolume0:double
+findArea(:double
Circle
V = Tr²h
-radius: double
A 92 a r2 + 2 nrh
+Circle(r: double)
+findArea0:double
+getRadius0:double
+setRadius(r: double): void
2ar
A = h(2ar)
A = 2ar² + h(2tr)
areas of top
bottom
circles
area of retangle
th me.com
Transcribed Image Text:11:16 E 19%! Circumference of a circle = C = 2r Volume of a cylinder=V=r*h Area of a cylinder A = 2arh+2r? CylinderTest Cylinder -height: double -sircle : Circle + maino +Cylinder(h: double, c: Circle) +findVolume0:double +findArea(:double Circle V = Tr²h -radius: double A 92 a r2 + 2 nrh +Circle(r: double) +findArea0:double +getRadius0:double +setRadius(r: double): void 2ar A = h(2ar) A = 2ar² + h(2tr) areas of top bottom circles area of retangle th me.com
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