Ascorbic acid, H2C6H6O6, is a diprotic acid with Ka1 = 7.9 * 10-5 and Ka2 = 1.6 * 10-12.  What is the pH of a 0.709 M solution of ascorbic acid?

Q: What is the pH of a solution that contains 0.10 M HCl and 0.10 M acetic acid (HC2H3O2)? Ka for…

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Q: A solution of 0.20 M hydrazoic acid has a pH of 3.21. What is the Ka of hydrazoic acid?

A: We have to calculate the Ka of acid.

Q: Calculate the pH of a 0.350 M solution of benzoic acid. Benzoic acid is a weak monoprotic acid with…

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Q: What is the pH of a solution that is 0.12 M in acetic acid, HC2H3O2, and 0.50 M in sodium acetate,…

A: Given [salt] = [sodium acetate] = 0.5 M [Acid] = [Acetic Acid] = 0.12 M Ka of acetic acid = 1.8*10-5

Q: Determine the pH of each of the following solutions. (a) 0.246 M hydrocyanic acid (HCN) (weak…

A: In chemistry, pH ( "potential of hydrogen" or "power of hydrogen") is a scale used to specify the…

Q: What is the pH of a solution that is 0.15 M NH4Cl and 0.35 M NH3?   The Ka of NH4Cl is 5.01 x…

A: In this question , we have to calculate the correct pH of given problem by the help of…

Q: The Kb of dimethylamine [(CH3)2NH] is 5.90x10–4 at 25°C. Calculate the pH of a 0.203 M  solution of…

A: This problem is based upon basic strength of base or dissociation constant for the base. Since…

Q: Methylamine, CH3NH2, has a Kb = 4.40 x 10-4. What is the pH of a 0.450 M  solution of methylamine?

A: Methylamine, CH3NH2 is a weak base which undergoes partial dissociation in aqueous medium. Let the…

Q: Determine the pH

A: The scale which is used to analyze the acidity and basicity of an aqueous solution is called as pH…

Q: Which of the following is the pH of a solution with [H3O+] = 1.0 x 10-9? Select one: a. 1.00 b.…

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Q: Calculate the pH and percent ionization of 0.150 M ascorbic acid K31 = 7.9x 10-5 ascorbic acid,…

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Q: Calculate the pH of a 0.25M solution of formate ion (HCOO-) at 250 C.  The pKa for formic acid…

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Q: The Kb of dimethylamine [(CH3)2NH] is 5.90×10-4 at 25°C. Calculate the pH of a 1.15×10-3 M  solution…

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Q: What is the pH of a 0.79 M solution of methylamine (CH3NH2, Kb = 4.4 x 10–4) at 25oC?

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Q: NH3 is a weak base (Kb=1.8×10−5Kb=1.8×10−5) and so the salt NH4Cl acts as a weak acid. What is the…

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Q: calcualate the pH of a 0.15 M solution of pyruvic acid ka of pyruvic acid is 4.1x10^-3

A: Given: Molarity or concentration of pyruvic acid = 0.15M Ka of pyruvic acid = 4.1 × 10-3

Q: Three (3) 0.10 M acid solutions were prepared and their pH values were recorded. Match the solution…

A: The acidic character of an organic compound depends on the stability of the resulting conjugate…

Q: Saccharin, a sugar substitute, is a weak acid with pKa = 2.32at 25 °C. It ionizes in aqueous…

A: Since the reaction given is HNC7H4SO3(aq) ⇌ H+(aq) +HNC7H4SO3-(aq) hence assuming that y…

Q: What is the pH of a 0.010M solution of acetic acid? Ka for acetic acid is 1.8 x 10-5

A: Given :-  [CH3COOH] = 0.010 M  Ka = 1.8 × 10-5  To calculate :-  pH of solution     Ka is the ratio…

Q: What is the pH of a solution that is 0.26 M CH3NH2 (methylamine) and 0.38 M CH3NH3Cl (methylammonium…

A: The basic buffer may be explained as the solution mixture which hold the weak base along with its…

Q: The Ka of a weak acid is 5.42 x 10-5. What is the pKb of its conjugate base?

A: Ka = 5.42 × 10-5 (given )  pKa = - log [Ka]  pKa = - log ( 5.42 × 10-5 )  pKa = 4.266

Q: NH3 is a weak base (K, = 1.8 x 10-5) and so the salt NH¼C1 acts as a weak acid. What is the pH of a…

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Q: The substance benzoic acid (C6H5COOH) is a weak acid (Ka = 6.3×10-5).What is the pH of a 0.258 M…

A: 1) Given: Concentration of C6H5COOK = 0.258 M The hydrolysis reaction of C6H5COO- coming from…

Q: Ascorbic acid (vitamin C, C6H8O6) is a diprotic acid (Ka1 = 8.0×10–5 and Ka2 = 1.6×10–12). What is…

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Q: What is the pH of 0.80 M methylamine (CH3NH2). Kb = 4.4x10-4.

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Q: The pH of a 0.05 M NaOH solution at 25 °C is: O 10.3 O 12.7 O 11.5 O 13.1 O13.8

A: pH of solution is calculated using relation pH + pOH = 14

Q: The pH of a 0.5 M aqueous solution of formic acid, HCHO2, at 25.0 °C is 2.0. What is the value of Ka…

A: pH tells us about the acidic or alkaline values of a solution. Dissociation of a weak acid depends…

Q: Ascorbic acid (vitamin C, C6H8O6) is a diprotic acid (Ka1 = 8.0×10–5 and Ka2 = 1.6×10–12). What is…

A: For first ionization :  pH = 0.5pKa1 - 0.5logC ..(1) Here, pKa1 = -logKa1 = -log(8*10^-5) = 4.097 C…

Q: The base protonation constant K, of lidocaine (C„H2,NONH) is 1.15 × 10 °. 14 Calculate the pH of a…

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Q: Ascorbic acid (vitamin C, C6H8O6) is a cliprotic acid (Ka1= 6.8 x 10-5 and Ka2 = 2.7 x 10-12). What…

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Q: (Q12) Hydrazoic acid (HN3) is a weak acid with a Ka of 2.5 x 10-5. What will be the equilibrium pH…

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Q: The value pKw is 11.05 at 78 °C. What is the pH of a neutral solution at the same temperature? Enter…

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Q: For H2CO3, Ka1= 4.3 x 10^-7, Ka2= 4.7 x 10^-11. What is the pH of a 0.28 M solution of carbonic…

A: H2CO3 is a weak acid.  pH = 0.5pKa - 0.5logC ....(1) Here, pKa1 = -logKa1 = -log(4.3*10^-7) = 6.37…

Q: The Kb for aniline (C6H5NH2) is 4.3 x 10-10. What is the pH of a 0.15 M solution of aniline?

A: From the ICE table, we have

Q: What is the Ka of hydrazoic acid if a 0.020 M hydrazoic acid aqueous solution has a pH of 3.22?

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Q: What is the pH of 0.278 M diethylammonium iodide, (C2H5)2NH2I.  The Kb of diethylamine, (C2H5)2NH,…

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Q: Calculate the pH of a 10 M C5H5NHCl (aq) (pyridine chloride salt of pyridine) at 25 °C.  The base…

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Q: The pH of a 1.50 M solution of anilinium chloride (C6H5NH3Cl) is _____.   Kb(C6H5NH2) = 4.3 × 10‒10…

A: Given,Kb(C6H5NH2) = 4.3 × 10‒10[C6H5NH3Cl] = 1.5 M

Q: The Kb of dimethylamine [(CH3)2NH] is 5.90x10–4 at 25°C. Calculate the pH of a 0.103 M  solution of…

A: Given : Concentration of (CH3)2NH = 0.103 M And Kb of (CH3)2NH = 5.90 X 10-4  Since (CH3)2NH is a…

Q: What is the pH of a solution that is 0.12 M in acetic acid, HC2H3O2, and 0.50 M in sodium acetate,…

A: Given data [sodium acetate]=0.50 M[acetic acid]=0.12 MKa=1.8×10-5   pH of weak acid and their salt…

Q: What is the pH of a 0.040 M solution of benzoic acid (Ka = 6.3 × 10-5) at 25ºC?

A: Given : Concentration of benzoic acid i.e C6H5COOH = 0.040 M And Ka of C6H5COOH = 6.3 X 10-5  Since…

Q: What is the pH of a grapefruit that contains 0.007 M citric acid solution (C;HgO;)? CH3O;(aq) +…

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Q: Calculate the pH of a 27 mg/L solution of hydrocyanic acid (HCN). The pKa of hydrocyanic acid is…

A: Given: The concentration of hydrocyanic acid is 27 mg/L. The pKa of hydrocyanic acid is 9.3.

Q: A diprotic acid, H2A, has Ka1 = 3.4 x 10 4 and Ka2 = 6.7 x 10-9. What is the pH of a 0.28 M solution…

A: Given: The molarity of the solution of H2A is 0.28 M The value of Ka1 is 3.4 x 10-4 The value of Ka2…

Q: Acetic acid (CH3COOH, ?a=1.80×10−5) is a weak acid, so the salt sodium acetate (CH3COONa) acts as a…

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Q: Calculate the pH of a 0.400 M CH3NH3Cl solution. Kb for methylamine, CH3NH2, is 4.4 × 10-4.

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Q: If the pH of a 1.00-in. rainfall over 1800 miles^2 is 3.90, how many kilograms of sulfuric acid,…

A: Given: pH = 3.90Area= 1800 miles2Ka2 = 0.012.

Q: What is the pH of a solution that is 0.11 M CH3NH2 (methylamine) and 0.15 M CH3NH3Cl (methylammonium…

A: Since the solution is having weak base CH3NH2 and its conjugate acid salt CH3NH3Cl  Hence the…

Q: Calculate the pH and % dissociation of a 0.100 M solution of propanoic acid (HC3H5O2). K,= 1.3x10-5…

A: Since you have asked multiple questions, we will solve the first question for you. If you want any…

States of Matter

The substance that constitutes everything in the universe is known as matter. Matter comprises atoms which in turn are composed of electrons, protons, and neutrons. Different atoms combine together to give rise to molecules that act as a foundation for all kinds of substances. There are five states of matter based on their energies of attraction, namely solid, liquid, gases, plasma, and BEC (Bose-Einstein condensates). 

Chemical Reactions and Equations

When a chemical species is transformed into another chemical species it is said to have undergone a chemical reaction. It consists of breaking existing bonds and forming new bonds by changing the position of electrons. These reactions are best explained using a chemical equation.