Assume that the complete combustion of one mole of glucose to carbon dioxide and water liberates 2870 kJ/mol(AGo'= -2870 kJ/mol).If one contraction cycle in muscle requires 67 kJ, and the energy from the combustion of glucose is converted with an efficiency of35% to contraction, how many contraction cycles could theoretically be fueled by the complete combustion of one mole ofglucose? Round your answer to the nearest whole number.суyclespermole glucose

Answered: Assume that the complete combustion of…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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In active muscle cells, the pO2 is about 10 torr at the cell surface and 1 torr at the mitochondria(the organelles where oxidative metabolism occurs). Calculate the percentage of bound oxygentransported to the mitochondria of muscle cells by myoglobin (KD = 2 torr).
Twenty-three milligrams of glucose were eaten by the bacteria Sanacoccus pumasareus. Calculate the hypothetical amount of ATP your patient can generate under aerobic respiration with this amount of glucose. (Note: Glucose MW-180.16 g/mole; 1 mole= 6.02 x 1023 molecules (Avogadro's number)). 2.8 x 10^24 ATPs 02.9 x 10^21 ATPs 028 x 10-21 ATP5 029 x 10 24 ATPS Lacks information, cannot be determined
a) (1) Calculate the physiological AG (not AG.) for the reaction: Phosphocreatine + ADP - creatine + ATP Given; Phosphocreatine + H;0 - creatine + Pi ADP + Pi → ATP + H;0 AG.' -43 kJ/mol AG.- +30.5 kJ/mol at 25°C as it occurs in the cytosol of neurons, in which phosphocreatine is present at 4.7 mM, creatine at 1.0 mM, ADP at 0.20 mM, and ATP at 2.6 mM. (R = 8.315 JK-' mol-) (ii) Caleulate the free energy change at standard conditions for the following reaction: Acetaldehyde + NADH + H* + Ethanol + NAD* The half- reactions are: Acetaldehyde + 2H + 2e + Ethanol E°- - 0.20V NAD-+ 2H- + 2e ++ NADH + H- E=-0.32V (F= 96.485 kJ/V/mol)
Consider the following phosphoryl group transfer reaction which is the first step in glucose catabolism by glycolysis: Glucose + ATP + Glucose 6-phosphate + ADP The AG for the reaction is -16.7 kJ/mol. (R= 8.314 J/(K. mol) (a) Calculate Keq for the reaction at 25°C (b) What is the ratio of [Glucose 6-phosphate] to [Glucose] if the ratio of [ADP] to [ATP] is 10?
Walking consumes approximately 100 kcal/mi. In the hydrolysis of ATP (ATP → ADP + Pi), the reaction that drives muscle contraction, ΔG°′ is −7.3 kcal/mol (−30.5 kJ/mol). Calculate how many grams of ATP must be produced to walk a mile. ATP synthesis is coupled to the oxidation of glucose (ΔG°′ = −686 kcal/mol). How many grams of glucose are actually metabolized to produce this amount of ATP? (Assume that only glucose oxidation is used to generate ATP and that 40% of the energy generated from this process is used to phosphorylate ADP. The gram molecular weight of glucose is 180 g and that of ATP is 507 g.)
What is the free energy change for generating the electrical imbalance of protons in respiring mitochondria in culture, where Δψ is 150 mV? (Express your answer in kJ/mol using 3 significant figures.)
Intracellular concentrations in resting muscle are as follows: fructose- 6-phosphate, 1.0 mM; fructose-1,6-bisphosphate, 10 mM; AMP, 0.1 mM; ADP, 0.5 mM; ATP, 5 mM; and P, 10 mM. Is the phosphofructokinase reac- tion in muscle more or less exergonic than under standard conditions? By how much?
What terms would best describe the above coupled reaction? (If the DGo for ATP hydrolysis into ADP + inorganic phosphate is -7.3 kcal/mole, and the DGo for maltose synthesis from glucose + glucose is +3.7 kcal/mole, calculate the standard free energy change for the combined reaction of ATP + glucose + glucose g ADP + maltose + inorganic phosphate.) it is non-spontaneous and endothermic (because the overall DGo is negative) it is spontaneous and exothermic (because the overall DGo is negative) it is non-spontaneous and endothermic (because the overall DGo is positive) it is spontaneous and exothermic (because the overall DGo is positive) it is non-spontaneous and exothermic (because the overall DGo is negative)
The complete combustion of palmitate and glucose yields 9781 kJ ∙ mol−1 and 2850 kJ ∙ mol−1 of free energy, respectively. Compare these values to the free energy (as ATP) obtained though catabolism of palmitate and glucose under standard conditions. Which process is more efficient?
Inside cells, the AG value for the hydrolysis of ATP to ADP + Pi is approximately -50 kJ/mol (-12 kcal/mol). Calculate the approximate ratio of [ATP] to [ADP][Pi ] in cells at 37°C. AG = AG + RT InKe R= 8.315 x 10³ kJ mol deg T= 298 K Table 15.1 Standard free energies of hydrolysis of some phosphorylated compounds Compound kJ mol- kcal mol- Phosphoenolpyruvate 1,3-Bisphosphoglycerate Creatine phosphate ATP (to ADP) -61.9 -14.8 -49.4 -11.8 -43.1 -10.3 -30.5 - 7.3 - 5.0 Glucose 1-phosphate Pyrophosphate Glucose 6-phosphate -20.9 -19.3 -4.6 -13.8 3.3 Glycerol 3-phosphate - 9.2 2.2 biochemistry
Enzymes Calculate the AG between glucose and ATP catalyzed by hexokinase: glucose + ATP glucose-6-phosphate + ADP Is the reaction spontaneous?| Given data: Glucose-6-phosphate + H2O glucose + P; AG' = -3138 cal/mole ATP+H,O =ADP + P. AG' = -7700 cal/mole
Calculate the AG for the following summary equations by showing the individual reactions and their AG's as well as the summary equation and its AG". a. Creatine phosphate + ADP > ATP+ creatine b. 1,3 kisphosphoglycerate + ADP → ATP + 3-phosphoglycerate 2.

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