Async: Dihybrid Practice T= Long Trunks t= Short trunks E= Big ears e = small ears Use the information about elephants in the box to complete the statements below. Two elephants were crossed with the following genotypes. TtEe x Ttee. 1. What is the probability of the zygote having long trunks and big ears?: 2. What is the probability of the zygote having short trunks and small ears? :: 1/8 : 1/2 : 5/8 : 3/8 : 1/4
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- Async: Dihybrid Practice T= Long Trunks t= Short trunks E= Big ears e = small ears Use the information about elephants in the box to complete the statements below. Two elephants were crossed with the following genotypes. TTEE x Ttee. 1. What is the probability of the zygote having long trunks and big ears? 2. What is the probability of the zygote having short trunks and small ears? :: 0% : 25% :: 50% : 75% : 100% Support | Schoology Blog | PRIVACY POLICY I Te EnglishPretending that Park shin-hye is heterozygous for A blood type marries Choi Tae-joon whose blood type is O. Show the possible blood types of their future children. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:Predict the outcomes of the following situations. genotype of the parents Punnett square genotypic ratio phenotypic ratio conclusion/answer to the question(s) Mr. Dalisay comes from an elite family in the province who desperately wanted to have a boy as his first born child so that his father, Mr. Flavio Dalisay III, would hand over the family sacred relic, the Balaraw of Panday, to him instead of his other brother. There were rumors that Mr. Dalisay arranged for the exchange of the babies in the hospital to secure his heir. Mr. and Mrs. Lizardo received baby #1 and Mr. and Mrs. Dalisay received baby #2. Is this rumor true? Blood typing tests on the parents and the babies showed the following results: Mr. Lizardo: Type A Mr. Dalisay: Type AB Mrs. Lizardo: Type O Mr. Dalisay: Type O Baby #1 (Girl): Type A Baby #2 (Boy): Type O Were the babies switched? How do you know whether they were, or they weren’t?
- Complete a Punnett Square. Then list the Genotype ratios of the offspring and describe their phenotypes. ex.) A green pea plant (Gg) is crossed with a yellow pea plant (gg). G Genotype ratios: 0 GG : 2 Gg : 2 gg Gg gg Phenotypes: 2 green : 2 yellow Gg gg gGiven the allelic frequency of A = .5 , answer the following 1. What is the homozygous dominant frequency ? 2. What is the allellc of a? 3. What is the heterozygous frequency ?Imagine you have a blood group of "X" which is recessive and expressed by xx. The dominant blood groups are Y and Z, where homozygous of these alleles are expressed as YY and ZZ, respectively. What will be the genotype of your parents blood group? Why? Please explain in your own words. [Max 200 words]
- Using the two Hardy-Weinberg equations, calculate the allelic and genotypic frequencies. Tongue rollers [R_-]= 840, Non rollers [rr] = 160, Total = 1000 1. What are the phenotypic frequencies for tongue rollers? 0.84 2. What are the phenotypic frequencies for non-tongue rollers? 0.16 3. What is the allelic frequency for r? 0.4 4. What is the allelic frequency for R? 0.6 5. What is the homozygous dominant frequency? 6. What is the heterozygous frequency? 7. What is the homozygous recessive frequency?Cross a homozygous tall female carrier for hemophilia with a short normal male. Give genotypic and phenotypic ratios of the offspring. Use T = Tall, and t = short for one trait, and H =normal, and h = hemophilia for the second sex-linked trait. The Cross is: XHXhTT X XYtt . Question: What is the phenotypic ratio? a. 1:2:4:4 b. 4:4:4:4 c. 3:2:1:4 d. None is correctTable 7.4 Male Gametes (i^iDd) Write in the Gametes and Complete the Punnett Square Female Gametes (i^i^DD) What is the phenotype of the male parent? What is the phenotype of the female parent? What is the genotypic ratio of the offspring? What is the phenotypic ratio of the offspring?
- Name: Kian Hamilton Period: 8th Using Punnett Squares to do a Monohybrid Cross You can use a Punnett Square to figure out the possible gene combinations of offspring using a Punnett Square. Remember, the stronger gene is dominant and the one that is masked is recessive. Dominant genes are always written with CAPITAL letters and recessive genes are always written with lower case letters. If both genes in the pair are the same, the trait is homozygous. If both traits in the pair are different, the trait is heterozygous. The genetic makeup of the individual is the genotype and the observable physical characteristics are the phenotype. Here is a list of dominant and recessive traits. You will be using these traits to predict the results of various crosses. Trait Pod Shape Pod Color Flower Position Plant Height Dominant Smooth (S) Green (G) Axial (A) Tall (T) Recessive Constricted (s) Yellow (g) Terminal (a) Short (t) Follow the steps ahead for doing a Punnett Square. Cross a plant that is…In pea plants, the tall allele is dominant to the short allele and the yellow pea allele is dominant to the green pea allele. Complete the Punnett square and questions below using the information and parent cross below. TtYy x TTyy 1. Complete the Punnett squares below. T Y y TT Tt yy TT Tt Yy yy 2. The phenotypes for TTYY and TtYy are correct order to receive credit T-trait listed first then the Y-trait) and (make sure the traits are listed in the 2a. What is the chance of an offspring having these two traits? 3. The phenotype for ttyy is and (make sure the traits are listed in the correct order to receive credit T-trait listed first then the Y-trait) 3a. What is the chance of an offspring having these two traits? :: T :: Y :: y :: TT :: Tt :: tt :: YY :: Yy : yy :: tall :: short : yellow :: green : 0% : 12.5% :: 25% : 37.5% :: 50% :: 56.25% :: 75% :: 100%please show genotypic and phenotypic ratio 1.A male French Alpine (WwHH) is crossed with a female French Alpine (wwHh). Where W-White, w-gray, H-Horned, h-Polled. Give the phenotypic and genotypic ratio of their offspring.