At the instant the displacement of a 2.00 kg object relative to the origin is = (2.00 m) + (4.00 m) - (3.00 m) K, its velocity is = (2.61 m/s) + (1.57 m/s) + (6.37 m/s) R and it is subject to a force = (1.47 N) - (8.39 N) I + (8.16 N) Find the acceleration of the object ((a), (b) and (c) for , i and k components respectively) (a) Number Units (b) Number Units (c) Number Units

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At the instant the displacement of a 2.00 kg object relative to the origin is
(2.00 m)
+ (4.00 m)
- (3.00 m)
its velocity is
(2.61 m/s)
+ (1.57 m/s)
+ (6.37 m/s)
and it is subject to a force
(1.47 N)
- (8.39 N)
+ (8.16 N)
Find the acceleration of the object ((a), (b) and (c) for !,
k
components respectively)
and
(a) Number
Units
(b) Number
Units
(c) Number
Units
Transcribed Image Text:d k At the instant the displacement of a 2.00 kg object relative to the origin is (2.00 m) + (4.00 m) - (3.00 m) its velocity is (2.61 m/s) + (1.57 m/s) + (6.37 m/s) and it is subject to a force (1.47 N) - (8.39 N) + (8.16 N) Find the acceleration of the object ((a), (b) and (c) for !, k components respectively) and (a) Number Units (b) Number Units (c) Number Units
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