Problem 3:Find the equation for the line tangent to the parametric curve: at the points where t = 2 and t = -2.For t = 2, the tangent line (in form y = mx + b) isy =For t= -2, the tangent line isy =Xy==1³ -4t41² - 14

Answered: Image /qna-images/answer/8c23099e-cf2b-46a2-a208-eb6a2560ea9d.jpg

Answered: at the points where t = 2 and t = -2.…

at the points where t = 2 and t = -2. For t = 2, the tangent line (in form y = mx + b) is y = For t= -2, the tangent line is y = x = y = || 1³- 41²

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter4: Calculating The Derivative

Section4.1: Techniques For Finding Derivatives

Problem 36E: Find all points on the graph of fx=x3+9x2+19x-10 where the slope of the tangent line is -5.

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Problem 3:

Find the equation for the line tangent to the parametric curve:

at the points where t = 2 and t = -2.
For t = 2, the tangent line (in form y = mx + b) is
y =
For t= -2, the tangent line is
y =
X
y
=
=
1³ -
4t
41² - 14

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Step 1: Determine the tangent lines

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Step 2: Calculate the tangent line at t=2

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Step 3: Calculate the tangent line at t=-2

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