B.A cell with internal resistance of 1.0 n is connected in series witnS.D gresistor and 3.0 A. The voltage across the 5 n resistor is 5 V. (a) What current flows through the circuit? (b) What is the voltage across the 3 a resistor? icl What is the terminal voltage of the cell? (d) What is the emf of the cell?
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- 4. a. Determine the equivalent resistance of the "ladder" of equal 175 Q resistors shown here. In other words, what resistance would an ohmmeter read if connected between points A and B? R R R R. R R R R Bon RAB = b. What is the current through a 50.0 V battery connected between points A and B?If three resistors connected in series to a battery. Suppose R1 carries a current of 4.5A, R2 has a resistance of 22.50, and R3 dissipates 95W of power. What is the voltage across R3 and Resistance of R3 ? 1. Voltage (in V) across R3 %3D and 2. Resistance (in 2) of R3 =A. Determine the equivalent resistance fir the circuit.keep vaules in ohms B. Determine hiw much current the battery produces. keep vaules in amps C. Determine the voltage across R12 and R3; call these values V12 and V3, keep the vaules in volts. then usr ohms law: V=i r, to fkmd the current across R12 and R3; call tjese 12 and 13, keep these vaules in amps. D. use ohms law to caculare the voltages across R1 and R2; call these vaules V1 and V2, keep results in volts. Requivatont,scris= Sihi=R1 tket . kequivaknt, papli=Zi Ri =RI K You circuit are given the following below. combination Z Rz R3 where V is a 12 V battery; R1 is 330ohms R2 is 180 ohms R3 is 270 ohms please write all work legaie thanks :)
- The compressor on an air conditioner draws89.6 A when it starts up. The start-up time isabout 0.282 s.How much charge passes a cross-sectionalarea of the circuit in this time?Answer in units of C.increases because the volume of mercury is constant. 21. At what temperature will aluminum have a resistivity that is three times the resistivity copper has at room temperature? 22. You are working in n a laboratory that atudier thea) . The equivalent resistant seen by the source. b) The total current I. c) . . The voltage across the 2K resistor. 1 kN 1 kΩ> 4 kN 20V 3 kN 2 kN 6.6 kN
- A cylindrical conductor has resistance R0=40 ohms. If we decrease the radius of the conductor by a factor of 2, while keeping the rest fixed, what is the new resistance? b. A battery with emf of 12 V, with an internal resistance of r=.5 ohms is connected in series with this cylindrical conductor (with radius reduced). what is its terminal voltage? Keep at least 6 sig. figs.Solve the following: 1. How many nanocoulomb are there in 3.65 billion electrons ? 2. A 25 ampere electric current flows in a conductor in 75 millisecond. Find: a. current equivalent in mA? b. How many charges are transferred ? c. How much work is required to transfer if 3V is applied. 3. A charge of 3.5 µC present in an electric field produces a force of 0.008 Newton. What is the intensity of the electric field ? 4. A charge of 0.6 µC is placed in an electrostatic field whose intensity is 3 x 105 N/C. How strong is the force acting on the charge ? 5. Two objects are both negatively charge with 0.04 coulomb each and 140 cm apart. What kind of force exist Between charges? How much? 6. Find the force that exist between two charges of 8.53 μC and 4.5 µC that 0.25 meters in air?At node 2, in the circuit below, Applying KCL gives: (use current directions at node 2) 2 A 82 ww V2 2 12 V 62 Select one: О а. V2- O b. 4 V, – V, 12 - ! V2 6. Oc. V-V2 4 8. V2-VI V2-12 V2 d. 4. 8 6. ww ww
- min firinim RI R. 11. In the circuit at right, let all internal resistances be r= 2o and all other R2 resistances be R = 80 a. The battery MFs are: R3 5 = 600 v 5, = 120 v 5 = 240 v R7 R6 What is the current through resistor (R,)? (in amps) a. 3.664 b. 4.580 c. 1.832 d. 2.748 e. 1.791 tüit. Pare, Ohmic ako. An exotic material has the following I-V curve. In which voltage region is the material Ohmic? I D B A-ELECTRICAL POTENTIAL AND CURRENT: V IR E-P P IV C Pt Series Circuits: Parallel Circuits: V, = V, + V,+ V, +. V, = V, = V, V, .. 1. 1. R, = R, + R, + R, +. RT R, R Based on the circuit drawn below: (Please use your VIRP chart) R = 15 Q V = 120 V R2 = 20 2 R3 5 2 W-