Based on the reactions: 1. 2NO2g) + 2NOg +O2e) 2N2O48) 2. 4NO() + 2N,Og +502(g) →4N2O42) 3. 2NO + O2(g → N2O4[e) Calculate the AH in kJ for the following reaction (write the result without decimals) 4N2O4(g) → 2N2O + 4NO2(g) + 302=) AH1 = -228.54 kJ AH2 = -488.46 kJ AH3 = -171.34 kJ Answer:

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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.146QP: Given the following (hypothetical) thermochemical equations:...
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Based on the reactions:
1. 2NO23) + 2NOg + O2e) → 2N2O42)
2. 4NO) + 2N2Og + 502(g) → 4N204(g)
3. 2NO) + O2(g)→ N½O4(g)
Calculate the AH in kJ for the following reaction (write the result without decimals)
4N2O4(2) 2N2O + 4NO2(g) + 302(g)
AH, = -228.54 kJ
AH2 = -488.46 kJ
AH3 = -171.34KJ
Answer:
Transcribed Image Text:Based on the reactions: 1. 2NO23) + 2NOg + O2e) → 2N2O42) 2. 4NO) + 2N2Og + 502(g) → 4N204(g) 3. 2NO) + O2(g)→ N½O4(g) Calculate the AH in kJ for the following reaction (write the result without decimals) 4N2O4(2) 2N2O + 4NO2(g) + 302(g) AH, = -228.54 kJ AH2 = -488.46 kJ AH3 = -171.34KJ Answer:
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