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int main{void main}
{
int myArray[100],numint,result;
printf("How many numbers to be entered?");
scanf("%d"&numint);
getNumbers(myArray,numint);
printNumbers(myArray,numint);
result=sumNumbers{myArray,numint};
printf("Sum of numbers entered=%d",result);
return 0;
}
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- int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…Which XXX completes the following code? public class MyGCDCalculator { public static int findGCD(int inNum1, int inNum2) { int tempVal; if (inNum1 inNum2) { tempVal = inNum1; %3D } else { if (inNum1 > inNum2) { XXX } else { tempVal findGCD(inNum1, inNum2 inNum1); %3D } } return tempVal; } public static void main (String[] args) { int num1 25; int num2 15; %3Dvoid funOne(int a, int& b, char v); void main() { int num1=10; char ch='A'; funOne(num1, 15,ch)<int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;Please explain this question void main() {int a =300; char *ptr = (char*) &a ; ptr ++; *ptr =2; printf("%d", a); }int pertambahan(int pilihan, int now){ int result; result =pilihan + now; return result;} int perkalian(int pilihan, int now){ int result; result = pilihan*now; return result;} int main(){ int NoR,initial; int now; int temp1, temp2; scanf("%d %d", &NoR, &initial); getchar(); now=initial; for(int o=0;o<NoR;o++){ char a,b; int pilihan1,pilihan2; scanf("%c %d %c %d",&a, &pilihan1,&b, &pilihan2); getchar(); if(a=='+') { if(pilihan1>=-1000 && pilihan1<=1000) { temp1 = pertambahan(pilihan1,now); } else{ temp1=-10000; } } else if(a=='x') { if(pilihan1>=-2 && pilihan1<=2){ temp1 = perkalian(pilihan1,now); } else { temp1=-10000; } } if(b=='+') { if(pilihan2>=-1000 && pilihan2<=1000) { temp2 = pertambahan(pilihan2,now); } else {…#include #include #include #define SIZE 5 int nums [SIZE] = [5,0,6,1,2); int main() { int i; pid_t pid; pid= fork(); if (pid == 0) { for (i = 0; i 0) { wait (NULL); } for (i = 0; i < SIZE; i++) printf("PARENT: %d\n", nums [i] + 1); /* LINE Y */ return 0; From the above-given program, please state what will be the output at lines X and Y. Explanation in detail required for output at both lines X and Y.Number of digits int main() {int c=0;int i=3856; int l=i; while(l>0) {l=l/10; c++; } printf("%d",c); return 0; } Summation of digits int main() {int sum=0; int i=384; int l=i; while(l>0) { sum+=l%10; l=l/10;} printf("%d",sum); return 0; }be recor #include #include minutes #include limit on int func(int, int, int, int); main(){ srand(time(NULL)); int a, b, c, fNum; printf("Choose three different numbers between 0-39:"); scanf ("%d%d%d", &a, &b, &c); fNum = func (a, b, c, 25); printf("\nThe result: %d", fNum); } int func (int ul, int u2, int u3, int iter){ srand (time (NULL)); int n1=0, i=0, count=0; for (;ichar[ ] letters=new char[5];int x = 0;while(x < 10){ar[x]='a';x++;}int FindSmallestVal() { int num = 0, min = 0; // reads num until the num > 0 while (num <= 0) { cin >> num; // finds the min value in the min,num min = num < min ? num : min; } // returns min return min; }struct Player { string firstName; string lastName; int hits; int runs; }; int main() { Player p = { "Jackie", "Robinson", 1518, 947 }; Player team[24]; Player *tPtr = team; team[0] = p; // INSERT CODE HERE } The statement tPtr = team+9; will assign the same memory address to tPtr as the statement tPtr = &(team[9]);SEE MORE QUESTIONSRecommended textbooks for youEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENTEBK JAVA PROGRAMMINGComputer ScienceISBN:9781337671385Author:FARRELLPublisher:CENGAGE LEARNING - CONSIGNMENT