Be sure to answer all parts. The dissociation of molecular iodine into iodine atoms is represented as 1₂(g) = 21(g) At 1000 K, the equilibrium constant K, for the reaction is 3.80 x 105. Suppose you start with 0.0453 mol of I₂ in a 2.27-L flask at 1000 K. What are the concentrations of the gases at equilibrium? What is the equilibrium concentration of 1₂? M What is the equilibrium concentration of I? M

Chemistry: Principles and Practice
3rd Edition
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Chapter14: Chemical Equilibrium
Section: Chapter Questions
Problem 14.52QE: Consider 0.200 mol phosphorus pentachloride sealed in a 2.0-L container at 620 K. The equilibrium...
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Be sure to answer all parts.
The dissociation of molecular iodine into iodine atoms is represented as
M
1₂(g) = 21(g)
At 1000 K, the equilibrium constant K, for the reaction is 3.80 x 105. Suppose you start with 0.0453
mol of 1₂ in a 2.27-L flask at 1000 K. What are the concentrations of the gases at equilibrium?
What is the equilibrium concentration of 1₂?
Check my work
What is the equilibrium concentration of I?
M
Transcribed Image Text:4 attempts left Be sure to answer all parts. The dissociation of molecular iodine into iodine atoms is represented as M 1₂(g) = 21(g) At 1000 K, the equilibrium constant K, for the reaction is 3.80 x 105. Suppose you start with 0.0453 mol of 1₂ in a 2.27-L flask at 1000 K. What are the concentrations of the gases at equilibrium? What is the equilibrium concentration of 1₂? Check my work What is the equilibrium concentration of I? M
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