Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ = 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk= 0.16. The final velocity of the block is 9.78 m/s. How fast is the block moving just before it reaches the second spring at the top of the hill? Simplifies to X₁ = 0 m h₁ = 0 m Vi = 9.78 m/s k = 2750 N/m m = 4.6 kg Wnc = 17.8 J 2 2 Wnc + mgh; +½ kx² +½ mv;² = mgh₁ + ½ kxf² + ½ mvf2 2 W₁ √nc + mv₁² = mghf +½ mvf2 W √nc +¹½ mv² — mghf_½ : mvf2 Vf=√(2W nc + v₁² - 2ght) X₁ = 0 m hf = 2.8 m Vi=? 2 v₁= √2(17.8 ) + (9.78 m/s)² – 2 (9.8 m/s) (2.8 m) Vf= 10.8 m/s

Principles of Physics: A Calculus-Based Text
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Chapter7: Conservation Of Energy
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Below is a conservation of energy problem. The solution to this problem is provided. Assess
whether the solution provided is correct or incorrect AND EXPLAIN WHY.
4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has
a spring constant of k₁ = 2750 N/m. After leaving the spring, it travels up a 28° incline to a
height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350
N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction
equal to uk= 0.16. The final velocity of the block is 9.78 m/s.
How fast is the block moving just before it reaches the second spring at the top of the hill?
Simplifies to
X₁ = 0 m
h₁ = 0 m
Vi = 9.78 m/s
k = 2750 N/m
m = 4.6 kg
W nc
=
17.8 J
2
2
Wnc + mgh₁ +½ kx;² +½½ mv;² = mghf + ½ kxf² + ½ mvf²
2
Wnc + mv₁² = mghf +½ mvf2
W₁
√nc +¹½ mv₁² — mghf _½ mvf2
=
Vf=√(2W nc+ V₁² - 2ghf)
x₁ = 0 m
hf = 2.8 m
Vi=?
V₁= 2(17.8 )) + (9.78 m/s)² – 2 (9.8 m/s²) (2.8 m)
Vf= 10.8 m/s
Transcribed Image Text:Below is a conservation of energy problem. The solution to this problem is provided. Assess whether the solution provided is correct or incorrect AND EXPLAIN WHY. 4.6 kg block is at rest against a horizontal spring that is compressed by 0.40 m. The spring has a spring constant of k₁ = 2750 N/m. After leaving the spring, it travels up a 28° incline to a height of 2.8 m. At the top of the hill is a second spring with a spring constant of k₂ = 350 N/m. The horizontal portions are frictionless, but the hill has a coefficient of kinetic friction equal to uk= 0.16. The final velocity of the block is 9.78 m/s. How fast is the block moving just before it reaches the second spring at the top of the hill? Simplifies to X₁ = 0 m h₁ = 0 m Vi = 9.78 m/s k = 2750 N/m m = 4.6 kg W nc = 17.8 J 2 2 Wnc + mgh₁ +½ kx;² +½½ mv;² = mghf + ½ kxf² + ½ mvf² 2 Wnc + mv₁² = mghf +½ mvf2 W₁ √nc +¹½ mv₁² — mghf _½ mvf2 = Vf=√(2W nc+ V₁² - 2ghf) x₁ = 0 m hf = 2.8 m Vi=? V₁= 2(17.8 )) + (9.78 m/s)² – 2 (9.8 m/s²) (2.8 m) Vf= 10.8 m/s
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