Boric acid dissolves in water according to the equation B(OH)3(aq) + H₂O → B(OH)2 (aq) + H+ (aq) Explain this reaction in terms of Lewis' theory of acid/base.

Chemistry for Today: General, Organic, and Biochemistry
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Chapter9: Acids, Bases, And Salts
Section: Chapter Questions
Problem 9.137E
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Boric acid dissolves in water
according to the equation
B(OH)3(aq) + H₂O → B(OH) (aq) + H+ (aq)
Explain this reaction in terms of
Lewis' theory of acid/base.
Transcribed Image Text:Boric acid dissolves in water according to the equation B(OH)3(aq) + H₂O → B(OH) (aq) + H+ (aq) Explain this reaction in terms of Lewis' theory of acid/base.
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