(c) A piece of material is subjected to tensile stress of 70 N/mm² in one direction and of 50 N/mm² in a direction at right angles to the previous one. Find fully the stresses on a plane the normal of which makes an angle of 40 degree with the 70 N/mm² stress.
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- (1) 1d. What is the shear stress on an element with principal stresses of 565 psi and -435 psi?At a point in a component, the state of stress is shown on the element below. Assume that the stress magnitudes are s,-7150 psi and Sy - 4475 psi. The stresses act in the directions indicated in the figuure. Determine the magnitude of the absolute maximum shear stress that acts at the point. Answer: Tmax psiThe state of stress at a point in a structural member may be represented by a two-dimensional stress system in which o, =100 N/mm², o,=-80 N/mm² and 7,, =45 N/mm². Determine the direct stress on a plane inclined at 60° to the positive direction of o, and also the principal stresses. Calculate also the inclination of the principal planes to the plane on which o, acts. Verify your answcrs by a graphical method. Ans. 6,= 16 N/mm², o1 =110.6 N/mm², ơn=-90.6 N/mm², 0= –13.3° and –103.3°. !!
- Element in plane ştress the stresses are and g = 97 MPa, g, = 76 MPa and T= 22 MPa. Determine the value of the first principal stress. Answer in MPa to one decimal place. Element in plane stress the stresses are and g, = 92 MPa, g= 66 MPa and I= 18 MPa. Determine the value of the maximum in-plane shear stress. Answer in MPa to one decimal place.At a point in a piece of elastic material there are three mutually perpendicular planes on which the stresses are are follows: tensile stress 50 N/mm2 and shear stress 40 N/mm2 on one plane, compressive stress 35 N/mm² and complementary shear stress on the third plane. Find : (a) the principal stresses and the positions of the planes on which they act, (b) the positions of the planes on which there is no normal stress.Find A. Minor stress B. Normal stress acting on plane AB C. Shear stress acting on plane AB
- Steel Stress-Strain diagram. Which of the following statements is NOT correct? Engineering stress is the stress computed using the original area and not the necking down area. The constant stress region is called the yield plateau or plastic range. The linear portion is also called the plastic range. The proportional limit, elastic limit, upper and lower yield points are very close to one another and are treated as a single point called the yield point.Q: A piece of material is subjected to tensile stress of 70 N/mm² in one direction and a compressive stress of 50 N/mm² in a direction at right angles to the previous one. Find fully the stresses on a plane the normal of which makes an angle of 40 degree with the 70 N/mm2 stress.The state of stress at a point in a machine component is given by o, = 120 MPa, o, = 55 MPa, G = -85 MPa, Gy = -55 MPa, ox = -75 MPa, and o, = 33 MPa. Construct the Mohr's circles of stress for this stress state and find the maximum shear stress.
- 2. (3 points) When loading is applied at a point on a body, the stress distributions at different cross sections are different. However, the stress distribution becomes uniform at locations far from the applied load. This is due to which principle? Name the principle. P Load distorts lines located near load P P C C Lines located away from the load and support remain straight P O avg A section a-a section b-b section c-c -Load distorts lines located near support Your answerCalculate the shear stress on a-a plane.e) Explain in a few words the difference between the normal stress, the shearing stress, and the bearing stress.