(C) (D) 8.44 x 10 5.63 x 1014 (E) 6.94 x 10 20 amber has afready vour PSU ID number (you dont

Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.60PAE
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1st question
(he molar solubility of europium (III) hydroxide is 1.37 x 10 M. What is the Kp value for the dissociation of
this ionic salt:
Eu(OH); (s) → Eu" (aq) + 3 OH (aq)
()
9.51 x 1027
3.52 x 1028
(B)
(C)
8.44 x 103
5.63 x 1014
(a)
6.94 x 10 20
(E)
mber has already been
(3)Write youar PSU ID number (you don't
(26)
Suppose that equal volumes of 0.114 M sodium chloride (NaCl) and 0.0888 M silver nitrate (AGNO3) are
combined. Given the Ksp for silver chloride is 1.77 x 1010, will a precipitate form under these conditions?
Cannot be determined without being given the volume of each solution that were combined
(B)
Yes, because Q = 0.0101
()
No, because Q = 0.0101
Yes, because Q = 0.00253
(a)
There is no possible cation/anion pairing that could result in the formation of a precipitate
(E)
OT X
Transcribed Image Text:(he molar solubility of europium (III) hydroxide is 1.37 x 10 M. What is the Kp value for the dissociation of this ionic salt: Eu(OH); (s) → Eu" (aq) + 3 OH (aq) () 9.51 x 1027 3.52 x 1028 (B) (C) 8.44 x 103 5.63 x 1014 (a) 6.94 x 10 20 (E) mber has already been (3)Write youar PSU ID number (you don't (26) Suppose that equal volumes of 0.114 M sodium chloride (NaCl) and 0.0888 M silver nitrate (AGNO3) are combined. Given the Ksp for silver chloride is 1.77 x 1010, will a precipitate form under these conditions? Cannot be determined without being given the volume of each solution that were combined (B) Yes, because Q = 0.0101 () No, because Q = 0.0101 Yes, because Q = 0.00253 (a) There is no possible cation/anion pairing that could result in the formation of a precipitate (E) OT X
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