can someone explain the logic for this code and why the output is what it is the outputs are for this code are 1 last line
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can someone explain the logic for this code and why the output is what it is
the outputs are for this code are
1
last line
for (I=1; I<=6; I++) {
if ( I%2)
printf(“%d\n”,I);
else
break;
printf(“last line\n”)
}
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- Modify the below program that the input values representingfractions are stored with denominators that are positive integers. You cannot require the user to only enter a positive denominator value; the user should not be inconvenienced by such a restriction. For example, whilst values of 1 / -2 are acceptable inputs for a fraction, the output representation should be -1 / 2. Your solution should check the denominator input; if it is negative, swap the sign of both numerator and denominator instance variables. //Import the essential package import java.util.ArrayList; import java.util.Scanner; //Define the class Fraction class Fraction { private int n, d; public Fraction() { //Initialize the values this.n = this.d = 0; } public Fraction(int n, int d) { //Initialize the variables this.n = n; this.d = d; } //Define the getter function getNum() that returns the numerator public int getNum() {…The pseudocode for implementing the Taylor series expansion is shown below. The pseudocode is designed to return the value of the value of e* correct to two decimal places. This also requires the use of the factorial function created in the previous section. INPUT x, OUTPUT ExpVal % Initial computation n- 0, xold - 0 xnew - xold + (x^n)/nl error = |xnew - xold| xold = xnew n-1 %Successive computations WHILE error 2 0.001 xnew - xold + (x^n)/nl error |xnew - xold xold - xnew n=n+1 END WHILE ExpVal = xnew Question 10: Write a script taylor.m that computes the value of the function e* for a given user input x. Provide La proof that your script works.The following function will correctly return true if its argument is an odd integer bool Isodd (int x) { return (x / 2 == 1); } True False
- while ( z >= 0 ) sum += z; identify the type of error in the above code with explanationDescribe what this code is doing and write its output. for (i=0;i<=2; i++) { for(j=0;j<=2;j++) { if (i=j) } break; else continue : cout<This code has a delay in the loop, during which time the user inputs will be ignored. So, please modify it and implement a solution that would trigger the needed function when there is an input. // Pin numbers written on the board itself do not correspond to Aurdino pinnumbers.Constants are defined to make using this board easierconst uint8_t BTN_PIN = 2;const uint8_t LED_PIN = 13;//assigning button;s previous state and LedSate to LOWuint8_t buttonPrevState = LOW;uint8_t ledState = LOW;//defining a new functionvoid setup(){// Assigning the types of input parameterspinMode(BTN_PIN, INPUT_PULLUP);//Assigning the types of output parameterspinMode(LED_PIN, OUTPUT);//begin of process detailsSerial.begin(9600);}void loop(){//assigning button state to be read modeuint8_t buttonState = digitalRead(BTN_PIN); //To print the following in output windowSerial.print(buttonState);Serial.print(buttonPrevState);Serial.print(ledState);Serial.println(""); //check if the button state presently is same…Q- tracing the following code and correct the error if you found the find the output x = [4 -2 3 -7 5 -1] ; %3D for k = 1:6 y(k) = 0; for n = 1:6 y(k) = y(k)+x(n)*exp(-11*2*pi* (k-1)*(n-1)/N); end end subplot(3, 1, 1); stem(y); title('FFT'); for n = 1:5 x1(n) = 0; for k = 1: 5 x1(n) =x1(n)+(1/N)*y(k)*exp(1i*2 pi (k-1) (n-1)/N); end end subplot(3,1,2); stem(x1); title('IFFT');What is the likelihood of an error in the REpitition code, also known as the Huffman code?Write your own definition for the function absfun( ) which receives real number x as an argument and returns its absolute value (i.e. abs(x)=|x|). Use this function in a program that reads numbers from the keyboard and prints their absolute values. [Don’t use math library] Sample Run Enter x :-3 Output: abs(-3) = 3.00 in c languageSEE MORE QUESTIONS