Can you please explain this code to me step-by-step? I especially did not get how s.append(x) is iteratively adding the elements back to the stack without any loop. Note: If you can spot any mistake in the function call, please point that out as well.   CODE To Delete Middle Element of a Stack: def deleteMid_util(s, sizeOfStack, current):                   #if current pointer is half of the size of stack then we      #are accessing the middle element of stack.     if(current==sizeOfStack//2):         s.pop()         return              #storing the top element in a variable and popping it.     x = s.pop()     current+=1              #calling the function recursively.     deleteMid_util(s,sizeOfStack,current)              #pushing the elements (except middle element) back      #into stack after recursion calls.     s.append(x) def deleteMid(s, sizeOfStack):     deleteMid_util(s, sizeOfStack, 0)         res = deleteMid([1,2,3,4,5], 5)   print(res)

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter18: Stacks And Queues
Section: Chapter Questions
Problem 16PE: The implementation of a queue in an array, as given in this chapter, uses the variable count to...
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Can you please explain this code to me step-by-step? I especially did not get how s.append(x) is iteratively adding the elements back to the stack without any loop.

Note: If you can spot any mistake in the function call, please point that out as well.

 

CODE To Delete Middle Element of a Stack:


def deleteMid_util(s, sizeOfStack, current):
    
        
    #if current pointer is half of the size of stack then we 
    #are accessing the middle element of stack.
    if(current==sizeOfStack//2):
        s.pop()
        return
        
    #storing the top element in a variable and popping it.
    x = s.pop()
    current+=1
        
    #calling the function recursively.
    deleteMid_util(s,sizeOfStack,current)
        
    #pushing the elements (except middle element) back 
    #into stack after recursion calls.
    s.append(x)

def deleteMid(s, sizeOfStack):
    deleteMid_util(s, sizeOfStack, 0)
    
  
res = deleteMid([1,2,3,4,5], 5)  
print(res)

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