Check that the point (1, -1, 1) lies on the given surface. Then, viewing the surface as a level surface fo a function f(x, y, z), find a vector normal to the surfa and an equation for the tangent plane to the surface at (1, −1,1). vector normal tangent plane: 2 = - 4x² - 4y² + 2z² = 2
Check that the point (1, -1, 1) lies on the given surface. Then, viewing the surface as a level surface fo a function f(x, y, z), find a vector normal to the surfa and an equation for the tangent plane to the surface at (1, −1,1). vector normal tangent plane: 2 = - 4x² - 4y² + 2z² = 2
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 39RE
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