clay of thickness 10 ft is drained on one side only. It has a hydraulic conductivity of h = 1.863 x 10-8 in/sec and a coefficient of volume compressibility mv = 8.6 x 10-4 in2/lb. Determine the ultimate value of the compression of the stratum by assuming a uniformly distributed load of 5250 lb/ft2 and also determine the time required for 20 percent and 80 percent c

clay of thickness 10 ft is drained on one side only. It has a hydraulic conductivity of h = 1.863 x 10-8 in/sec and a coefficient of volume compressibility mv = 8.6 x 10-4 in2/lb. Determine the ultimate value of the compression of the stratum by assuming a uniformly distributed load of 5250 lb/ft2 and also determine the time required for 20 percent and 80 percent c

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter11: Ground Improvement

Section: Chapter Questions

Problem 11.10CTP

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A stratum of normally consolidated clay of thickness 10 ft is drained on one side only. It has a hydraulic conductivity of h = 1.863 x 10^-8 in/sec and a coefficient of volume compressibility mv = 8.6 x 10^-4 in2/lb. Determine the time required for 20% consolidation by assuming a uniformly distributed load of 5250 lb/ft2. a.8.72 days b.157.50 days c.6.982 days d.125.64 days
A strata of normally consolidated clay of thickness 10 ft is drained on one side only. It has hydraulic conductivity of h = 1.863 x 10~ 8 in/sec and a coefficient of volume compressibility ra v = 8.6 x 10" 4 in 2 /lb. Determine the ultimate value of the compression of the stratum by assuming a uniformly distributed load of 5250 lb/ft 2 and also determine the time required for 20 percent and 80 percent consolidation.
Water flows at a rate of 0.09 m3/s upward through a sand sample with a coefficient of permeability of 27 cm/s. The thickness of the soil is 0.24 m and the area is 0.54 sq. m. Saturated unit weight is 18.9 kN/m3. a) Determine the hydraulic gradient (Ans. 0.617) b) Compute the effective stress at the middle of the sample (Ans. 354 N/m2) c) Compute the effective stress at the bottom of the sample. (Ans. 728 N/m2)
A stratum of normally consolidated clay of thickness 10 ft is drained on one side only. It has a hydraulic conductivity of h = 1.863 x 10^-8 in/sec and a coefficient of volume compressibility mv = 8.6 x 10-^4 in2/lb. Determine the time required for 80% consolidation by assuming a uniformly distributed load of 5250 lb/ft2.
A soil profile consists of two layers of soil with clay layer underlying the sand layer. The sand layer has a unit weight of 20 kN/m^3 having a thickness of 4 m. and the unit weight of the 2.5m layer of clay is 18 kN/m^3. Compression index of the clay is 0.22 with a void ratio of 1.30. Compute the effective stress (kPa) at the mid height of clay. Calculate the final settlement of the clay layer (mm) due to an increase of pressure of 30 kPa at the mid-height of the clay. Calculate the settlement (mm) when the water table rises to the ground surface.
Shear Stress 3. Please provide proper discussion and illustration. Clear and complete solution please thank you. It is known that the angle of internal friction for the soil comprising a granular deposit is 37°. At one depth in the deposit, the lateral pressure is 45 kPa, and this is considered the value of the minor principal stress. Use the Mohr’s circle analysis to determine the maximum verticalp ressure (major principal stress) that can be applied (i.e. the vertical pressure for incipient shear)
Example 22 a For a normally consolidated clay (c' = 0) these are the results for a consolidated drained triaxial test Chamber pressure = 104 kN/m² Deviator stress at failure = 125 kN/m² a) Find the angle of friction, ' (Answer: 22) b) Determine the angle 9 that failure plane makes with the major principle plan (Answer: 56) TOI-OHOMAI Institute of Technology Example 3 The equation of effective stress failure envelope for normally consolidated clayey soil is Tf = o'tan 27 A drained triaxial test was conducted with the same soil at the chamber confining pressure of 100 kN/m². Calculate the deviator stress at failure (Answer: 166.3 kN/m²)
stress and pore water pressure. 2- A soil profile consists of 10m of sand (Y=20 kN/m³) over 3m of organic silt (Y=17KN/m 0.5,0CR = 1,c, = 8 m²/year)over gravel. Initially, the water table is 2m below the ground surface and hydrostatic condition exists throughout the soil profile. Before constructing a structure on this site, the organic silt is preconsolidated by rapidly lowering the water table by 6m (to 8m below the ground surface) and simultaneously pumping from the gravel layer at such rate that the piezometric level in the gravel is lowered to the bottom of the organic silt. Compute settlement resulting from consolidation of the organic silt if the lowered ground water
A 1.5 m thick strata of sand has a dry unitweight of 15 kN/m3. A contractor passes a vibratory roller over this strata, whichdensifies it and increases its dry unit weightto 16.5kN/m3. Compute its new thickness. Hint: consider 1 m x 1 m column of soil.
A long embankment 30 m wide is to be built on ground. The net vertical pressure applied by the embankment (assumed to be uniformly distributed) is 90kpa. The soil profile and stress distribution beneath the center of the embankment is also shown. The value of mv for the upper clay is 0.35m2/MN, and for the lower clay mv=0.13m2/MN. Tthe permeabilities of the cllays are 10-10m/s and 10-11m/s for the upper and lower soil respectively. Determine the final settlement under the center of the embankment due to consolidation
Knowing that the compression index, Cc = 0.333, and the preconsolidation pressure s’c = 140 kPa with an initial void ratio e0 = 0.85 for a H = 3 m thick clay layer which is subjected to a new loading for an embankment resulting in a stress increase to 200 kPa; what is the expected consolidation settlement? Provide answer below in meters (m).
A clay formation having a depth of 4 m. underlies a sand formation having a depth of 3 m. The dry unit weight of sand is 16.5 kN/m3 and the saturated unit weights of clay and sand are 20.4 kN/m3 and 19.6 kN/m3 respectively. The groundwater table is at the interface of the sand and clay. Compute the effective stress at the bottom of clay. Use 3 decimal places in MPa.