Clipboard • Styles Paragraph Calculate and record the weight values in Newtons in the table below. This will be the force exerted at that particular position on the meter stick, due to the mass that is present ther O ● right side (all trials) ● Calculate and record the lever arm values in meters in the table below. Lever arm is the positive distance from the pivot, calculated as the difference between recorded position value Calculate and record the torque values in Nm in the table below. First calculate the weight force exerted at that point, and then multiply by the lever arm. (Angles are 90° for these tri Further calculations and analysis will be performed in the Data Analysis section that follows. left side (trial 1) left side (trial 2) left side (trial 3) mass 20.90 g + 50 g = kg 20.74 g + 100 g = 7 kg 20.74 g + 50 g = kg 20.74 g +30 g = kg Font W weight (N) E position D 75.00 cm 35.65 cm 25.30 cm C 15.55 cm 55 4 6 R TI lever arm (m) 75.00-50.20 cm = 50.20-35.65 cm = Data Analysis for Part One Your goal is to prove that the meter stick was in rotational equilibrium for each trial in Part One. To do this, you need to show that the left-side torque was equal to the right-side torque-but they won't be 2445 words Text Predictions: On Accessibility: Investigate Focus MU 6 HH Type here to search 3 m 50.20-25.30 cm = m O Ei 50.20-15.55 cm = V m T m G 6 torque (Nm) B H 9 5 N U 8 1 M PM K Edit O 64°F
Clipboard • Styles Paragraph Calculate and record the weight values in Newtons in the table below. This will be the force exerted at that particular position on the meter stick, due to the mass that is present ther O ● right side (all trials) ● Calculate and record the lever arm values in meters in the table below. Lever arm is the positive distance from the pivot, calculated as the difference between recorded position value Calculate and record the torque values in Nm in the table below. First calculate the weight force exerted at that point, and then multiply by the lever arm. (Angles are 90° for these tri Further calculations and analysis will be performed in the Data Analysis section that follows. left side (trial 1) left side (trial 2) left side (trial 3) mass 20.90 g + 50 g = kg 20.74 g + 100 g = 7 kg 20.74 g + 50 g = kg 20.74 g +30 g = kg Font W weight (N) E position D 75.00 cm 35.65 cm 25.30 cm C 15.55 cm 55 4 6 R TI lever arm (m) 75.00-50.20 cm = 50.20-35.65 cm = Data Analysis for Part One Your goal is to prove that the meter stick was in rotational equilibrium for each trial in Part One. To do this, you need to show that the left-side torque was equal to the right-side torque-but they won't be 2445 words Text Predictions: On Accessibility: Investigate Focus MU 6 HH Type here to search 3 m 50.20-25.30 cm = m O Ei 50.20-15.55 cm = V m T m G 6 torque (Nm) B H 9 5 N U 8 1 M PM K Edit O 64°F
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Transcribed Image Text:Clipboard
right side
(all trials)
left side
(trial 1)
Editing
Paragraph
Calculate and record the weight values in Newtons in the table below. This will be the force exerted at that particular position on the meter stick, due to the mass that is present there.
Calculate and record the lever arm values in meters in the table below. Lever arm is the positive distance from the pivot, calculated as the difference between recorded position values.
Calculate and record the torque values in Wm in the table below. First calculate the weight force exerted at that point, and then multiply by the lever arm. (Angles are 90° for these trials.)
Further calculations and analysis will be performed in the Data Analysis section that follows.
left side
(trial 2)
left side
(trial 3)
mass
20.90 g + 50 g =
kg
20.74 g + 100 g=
kg
20.74 g + 50 g =
kg
20.74 g +30 g =
Font
kg
weight (N)
52
W
LU
position
E
75.00 cm
35.65 cm
25.30 cm
15.55 cm
(201
$4
Y
lever arm (m)
75.00-50.20 cm =
LL
50.20-35.65 cm =
50.20-25.30 cm =
Data Analysis for Part One
2445 words 0
Your goal is to prove that the meter stick was in rotational equilibrium for each trial in Part One. To do this, you need to show that the left-side torque was equal to the right-side torque - but they won't be exa
Accessibility: Investigate
Text Predictions: On
Focus
Ee
O Type here to search
O Ri
50.20-15.55 cm =
%
m
PANG
V
L.O
5
E
T
m
3
torque (Nm)
10
B
h
Y
F
I
N
Σ
Styles
PM
Y
?b
64°F ^
11
Transcribed Image Text:trial 1
trial 2
trial 3
2445 words
right side torque (Nm)
"expected value"
(same as above)
(same as above)
Text Predictions: On Accessibility: Investigate
Type here to search
W
#
3
E
left side torque (Nm)
"measured value"
D
$
4
101
R
LLI
O i
%
5
T
G
% error
F
40
B
&
H
7
U
00
8
PM
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