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- Please let me know if these are true or false! In multiprocessors with a shared physical main memory, an access to a word of main memory always takes about the same amount of time no matter which word is being accessed and by which processor: T/F? When reading data from a magnetic disk, the rotational latency increases linearly with the size of the request: T/F? SSD is faster to access than magnetic disk, but slower than DRAM main memory: T/F? The primary purpose of RAID is for data backups: T/F? Typically, data parallelism offers greater opportunities for achieving highly-parallel execution than does functional parallelism: T/F? In MIPS systems, one way to implement locks is with the MIPS test-and-set machine language instruction: T/F?An address space in the memory map starts at address Ox40000000 and ends at address O×40000FFE. What is the size of the space if the data size is 2 bytes? 16k bytes 4k bytes 2k bytes 8k bytesConsider the interfacing of a RAM to an 8086 microprocessor as shown in the figure below. If the starting address of the RAM is 00000H. RAM1 = 64K , RAM2 = 64K , RAM3 = 32K , RAM4 = 64K ,and RAM5 = 32K bytes. What is the address of the last location of RAM3?
- Serial access memories are useful in applications whereA. Data consists of numbersB. Short access time is requiredC. Each stored word is processed differentlyD. Data naturally needs to flow in and out in the serial form.Carefully read each sentence in this question. You may agree/disagree with each sentence (consider each sentence separately) if you have a good justification for doing so (not in more than 2 lines for each sentence). “A daisy chaining technique could result in starvation.” “The received data is saved in contiguous memory regions in DMA transfer.” “The most difficult method of device identification is multiple interrupt lines.” “An interrupt request takes longer for the CPU to handle than a DMA request.” “The architecture of InfiniBand operation is layered.”What are the performance implications of serializing large objects?
- Suppose the RAM for a certain computer has 4M words, where each word is 16 bits long. What is the capacity of this memory expressed in bytes? If this RAM is byte addressable, how many bits must an address contain? If this RAM is word addressable, how many bits must an address contain?What is the cause of multipathing?When allocating process execution to the I/O queue, what are the advantages of doing so first? If the I/O is interrupted, what do you believe will happen? Will this have an impact on the CPU's burst rate? What do you mean by that?
- Suppose that a magnetic disk has an average seek time of 4 ms, a rotation rate of 5400 RPM, a transfer rate of 50 MB/second, a sector size of 512 bytes, and controller overhead of 2 ms. What is the average amount of time to read a single sector?Read-only memory (usually known by its acronym, ROM) is a class of storage media used in computers and other electronic devices that is non-volatile (non-changeable). Because data stored in ROM cannot be modified (at least not very quickly or easily), it is mainly used to distribute firmware (software that is very closely tied to specific hardware, and unlikely to require frequent updates). Figure 3.1 depicts a ROM block diagram which have k-bit address and an n-bit data. The contents of a ROM chip are defined once. Hence, we can use a constant array to model a ROM in VHDL. Basically, to name the size of a ROM is by stating ROM k x n, which represents ROM with k-bit address andn-bit data size. For example, ROM 4x8 (16 address location with each location containing 8-bit data). Question. Develop a code to allow the ROM operation works in synchronous when a read enable is asserted.• Generate and simulate the VHDL codes in Altera Quartus II.• Demonstrate and obtain the instructor…In order to build the whole of the binary code in a single pass over the source file, what obstacles does an assembler need to overcome? What are the key distinctions between code that has been written for a one-pass assembler and code that has been written for a two-pass assembler?