Combine the series voltage sources in Fig. 5.101 into a sin-gle voltage source between points a and b.YAN4 V+|||-8V++6V-Oba obo-a obo- 12 V +- 10 V +HO+5V -||||||후- 12 V ++18 V-- 12V +- 8V+6 V-8V++||6VHill+8V-4 Vt<-8V+VAINOHilt+4V-ob

Answered: Image /qna-images/answer/5ad483bc-5936-4f6b-8d73-e872581ee0cf.jpg

Combine the series voltage sources in Fig. 5.101 into a sin- gle voltage source between points a and b. RYAN IV 幸训 -8V + +6V - OF bo Go bo -10V+ -12V+ +5V- 训 - 12V+ + 18V- 李 - 12V + -8V+ 6V -8V + -6° 加 +8V- 4V 川 -8V+ JAIND 加 +4V- ob

Combine the series voltage sources in Fig. 5.101 into a sin- gle voltage source between points a and b. RYAN IV 幸训 -8V + +6V - OF bo Go bo -10V+ -12V+ +5V- 训 - 12V+ + 18V- 李 - 12V + -8V+ 6V -8V + -6° 加 +8V- 4V 川 -8V+ JAIND 加 +4V- ob

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter18: Resistive-inductive Parallel Circuits

Section: Chapter Questions

Problem 9PP: In an R-L parallel circuit, ET=240 volts, R=560 R = 560 2, and XL=330. Find reactive power.

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Concept explainers

Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

Combine the series voltage sources in Fig. 5.101 into a sin-
gle voltage source between points a and b.
YAN
4 V
+|||
-8V+
+6V-
Ob
a o
bo-
a o
bo
- 12 V +
- 10 V +
HO
+5V -
||||||
후
- 12 V +
+18 V-
- 12V +
- 8V+
6 V
-8V+
+||
6V
Hill
+8V-
4 V
t
<-8V+
VAINO
Hilt
+4V-
ob

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Step 1: Combine the series voltage source into single equivalent voltage source across a and b:

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Step 2: Combine Single voltage source for circuits a and b:

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Step 3: Combine Single voltage source for circuits c and d:

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