Question in photo 1. Complete the table below to describe the phenotypic consequences for a loss-of-function allele andseparately for a gain-of-function allele in each of the genes listed. This is in a somatic cells, in adiploid organism. Consequences should be at the cellular level. The table below considers twogenes and asks you to predict consequences if a cell is heterozygous and homozygous for theindicated allele, for both loss of function (LOF) and gain of function (GOF) alleles. You should alsoindicate if the genotypes could be inherited and if so, would it be a lethal genotype? Lastly, labeleach gene as either a proto-oncogene or a tumor suppressor gene.Be sure to state any assumptions you are making. See sample answer in first box.Type of alleleNormal GeneGenotype (+product (e.g.Loss of FunctionGain of Functionis wildtype, -is mutant)protein)functionPhenotype: E.g., noPhenotype:МҮС, аtranscriptionfactor thatphenotypic change at cellularor organismal levels(assuming + allele ishaplosufficient).stimulatesHeterozygoteCould inherit the LOF alleleprogression(+/-)b/c it shouldn't be lethalfrom G1 to Sduring development (basedphase (proto-oncogene).on wild-type haplosufficiencyassumption) Homozygote(-1-)Heterozygote(+/-)VHL. Normallysuppresses celldivision (tumor-suppressorgene).Homozygote(-/-)

During the development of cancer two genes are contributed that are; proto-oncogene and…

Answered: Complete the table below to describe…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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1. Please consider the following pedigree. I 1 II 1 a) Assume that colour is controlled by a single sex-influenced gene where green is expressed preferentially in males. Individuals I-1 and I-2 are homozygous for red and green respectively. Which individual/s in generation II will be red? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be green?
5 f There are two genes that determine the coat colour expression in dogs: eumelanin and merle. These genes are located on two separate chromosomes. For the eumelanin gene, black coat colour (E) is dominant over red coat colour (e). The merle gene controls the degree to which these coat colours are expressed through incomplete dominance. The following table describes the merle gene expression. Genotype MM Mm mm Phenotype White AAY Half colour (Grey or light red) Full colour (Black or Red) 1. If a dog breeder wants to determine the unknown genotype of a dog, what colour of dog must she use as a testcross? 2. A white dog was testcrossed, and all of the puppies had light red coats. What is the genotype of the white dog? Use a Punnett square to show your work. Hint - When a trait is controlled by two genes, an individual's genotype consists of 4 letters. = = = B I 123 ||| 14 E E I ос C GO * ●● ● ●0 00 00 00 ✓ C U up X₂ x²
1. Please consider the following pedigree. I 1 2 II 1 a) Assume that colour is controlled by a single sex-influenced gene where orange is expressed preferentially in females. Individuals I-1 and I-2 are homozygous for orange and blue respectively. Which individual/s in generation II will be blue? b) If colour is a controlled by cytoplasmic DNA, which individual/s in generation II will be orange?
I. Male Drosophila from a true-breeding wild-typestock were irradiated with X-rays and then mated withfemales from a true-breeding stock carrying the following recessive mutations on the X chromosome:yellow body (y), crossveinless wings (cv), cut wings(ct), singed bristles (sn), and miniature wings (m).These markers are known to map in the order:y - cv - ct - sn - mMost of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and snphenotypes. When this exceptional ct sn female wasmated with a male from the true-breeding wild-typestock, twice as many females as males appearedamong the progeny.a. What is the nature of the X-ray-induced mutationpresent in the exceptional female?b. Draw the X chromosomes present in the exceptional ct sn female as they would appear duringpairing in meiosis.c. What phenotypic classes would you expect to seeamong the progeny produced by mating the exceptional ct sn female with a normal male from a truebreeding wild-type…
Please explain how you do this question step by step I am very confused! thank you:) You have three independent mutant alleles in the Drosophila gene no-antenna: nan1, nan2 and nan3. You determine the phenotype of Drosophila that are heterozygous for the three alleles (heterozygous for a wild-type allele and a mutant allele), and that are homozygous for the three mutant alleles. The antenna is composed of three segments that are followed at the distal end by a feathery arista (that is the antenna is composed of three segments and an arista). Allele nan1 nan2 nan3 heterozygous Wild-type No arista Wild-type homozygous No arista No antenna No antenna nan1 is a __x__ allele, nan2 is a __y__ allele, and nan3 is a __z__ allele. X Y Z A Dominant negative Null Hypomorphic B Null Dominant negative Hypomorphic C Null Hypomorphic Dominant negative D Hypomorphic Dominant negative Null E Dominant negative Hypomorphic Null Referencing the table above, select the…
In Drosophila, three autosomal genes have the following map:20 m.u. 10 m.u.a b ca. Provide the data, in terms of the expected numberof flies in the following phenotypic classes, whena+ b+ c+/ a b c females are crossed to a b c / a b c males. Assume 1000 flies are counted and that nointerference exists in this region.a+ b+ c+a b ca+ b ca b+ c+a+ b+ ca b c+a+ b c+a b+ cb. If the cross was reversed, such that a+ b+ c+ / a b cmales are crossed to a b c / a b c females, howmany flies would you expect in the same phenotypic classes?
The following genotypes of two independently assorting autosomal genes determine coat color in rats:A-B- (gray); A-bb (yellow); aaB-(black); aabb (cream)A third gene pair on a separate autosome determines whetherany color will be produced. The CC and Cc genotypes allow coloraccording to the expression of the A and B alleles. However,the cc genotype results in albino rats regardless of the A and Balleles present. Determine the F1 phenotypic ratio of the followingcrosses: (a)AAbbCC * aaBBcc; (b) AaBBcc * AABbcc;(c) AaBbCc * AaBbcc.
A complex biochemical pathway is shown below, along with the alleles that either promote or inhibit each step of the pathway leading to a phenotype. Gene A has alleles A and a, B has alleles B and b, and so forth. Genes B and C are duplicate dominant epistatic lethal as heterozygotes (i.e. Bb Cc are lethal). Genes D and E are duplicate dominant epistatic (i.e. dd eg = desired phenotype). If I were to cross AA Bb cc Dd Ee with aa BB Cc Dd e, (i) (ii) What proportion of all offspring don't show the phenotype? What proportion of offspring survive? Gene A Gene B B Gene D a Gene C Gene E
In guinea pigs, the allele for black fur (B) is dominant over the allele for brown (b) fur. A black guinea pig is crossed with a brown guinea pig, producing five F1 black guinea pigs and six F1 brown guinea pigs. Q. How many copies of the black allele (B) will be present in each cell of an F1 black guinea pig at the following stages: G1, G2, metaphase of mitosis, metaphase I of meiosis, metaphase II of meiosis, and after the second cytokinesis following meiosis? Assume that no crossing over takes place.
In rats, the following genotypes of two independently assorting autosomal genes determine coat color: A-B- (gray) A-bb (yellow) aaB- (black) aabb (cream) A third gene pair on a separate autosome determines whether or not any color will be produced. The CC and Cc genotypes allow color according to the expression of the A and B alleles. However, the cc genotype results in albino rats regardless of the A and B alleles present. Determine the F1 phenotypic ratio of the following crosses: (a) AAbbCC * aaBBcc (b) AaBBCC * AABbcc (c) AaBbCc * AaBbcc (d) AaBBCc * AaBBCc (e) AABbCc * AABbcc
Which of these predictions would you make for a gene that is haplosufficient and essential for viability? A diploid heterozygous for a null allele and the wild-type allele will be viable. A diploid heterozygous for a null allele and a wild-type allele will be nonviable. A diploid homozygous for a null allele will be nonviable. A null allele would lead to nonviable haploid cells.
Retinoblastoma can be seen as a familial cancer, inherited in an autosomal recessive manner (RB-/RB-), individuals heterozygous for the RB+ and RB- alleles can develop tumor as a result of… A mitotic crossover that leads to homozygosity for RB+ in some cells and RB- in other cells A meiotic mutation in the RB+ allele that leads to homozygosity for RB+ A somatic mutation in the RB- allele that leads to homozygosity for RB+ The fact that RB- is dominant to RB+

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