Composition (ars C) 10 15 20 1538C Lever Rule: 1493°C 400 Wa = 2500 R+S 1394C 200 1147C Wp R+S 2.14 4.30 7. Austenite 2000 000 912C + Fegc s00 1500 727°C 0.76 0.022 500 a, Ferite a+ Fegc Cementite FeC. 1000 400 6.70 (Fe) Composition (wes C) mass fraction of totala, Ferrite and total Cementite in an iron-carbon alloy are 6.35 kg and 1.65 kg bectively, and cooled just below the eutectoid temperature. alleu luaor

Elements Of Electromagnetics
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5. Phase Diagram.
Composition (at% C)
1600
1538°C
10
15
20
25
Lever Rule:
-1493°C
Wa =
R+S
1400
2500
1394°C
1200
R
1147°C
Y. Austenite
2.14
4.30
2000
R+S
1000
912°C
+ Fegc
800
1500
727°C
0.76
'0.022
600
a, Ferrite
a+ Fegc
Cementite (FegC)
1000
400
6
6.70
(Fe)
Composition (we% C)
The mass fraction of totala, Ferrite and total Cementite in an iron-carbon alloy are 6.35 kg and 1.65 kg
respectively, and cooled just below the eutectoid temperature.
a) Determine the concentration (composition) of carbon in this alloy (wt% C).
b) Determine the Pearlite fraction in kg.
c) Is this hypo eutectoid, hypo eutectic, hyper eutectoid or hyper eutectic? Justify your answer.
d) Is this composition of steel: Low, Medium, or High Carbon content? Justify your answer.
e) Draw schematic microstructure from above composition at T= 1100 °C, just below 727 °C, 450 °C:
Temperature ("C)
Temperature ("F)
Transcribed Image Text:5. Phase Diagram. Composition (at% C) 1600 1538°C 10 15 20 25 Lever Rule: -1493°C Wa = R+S 1400 2500 1394°C 1200 R 1147°C Y. Austenite 2.14 4.30 2000 R+S 1000 912°C + Fegc 800 1500 727°C 0.76 '0.022 600 a, Ferrite a+ Fegc Cementite (FegC) 1000 400 6 6.70 (Fe) Composition (we% C) The mass fraction of totala, Ferrite and total Cementite in an iron-carbon alloy are 6.35 kg and 1.65 kg respectively, and cooled just below the eutectoid temperature. a) Determine the concentration (composition) of carbon in this alloy (wt% C). b) Determine the Pearlite fraction in kg. c) Is this hypo eutectoid, hypo eutectic, hyper eutectoid or hyper eutectic? Justify your answer. d) Is this composition of steel: Low, Medium, or High Carbon content? Justify your answer. e) Draw schematic microstructure from above composition at T= 1100 °C, just below 727 °C, 450 °C: Temperature ("C) Temperature ("F)
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