Computer Science ef get_syllable_count(poem_line: POEM_LINE, words_to_phonemes: PRONUNCIATION_DICT) -> int:
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Computer Science
ef get_syllable_count(poem_line: POEM_LINE,
words_to_phonemes: PRONUNCIATION_DICT) -> int:
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- Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for the rugged hero to tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The number of ways that a positive integer n can be represented as a sum of consecutive integers is called its politeness, and can also be computed by tallying up the number of odd divisors of that number. However, note that the linked Wikipedia de0inition…Count consecutive summers def count_consecutive_summers(n): Like a majestic wild horse waiting for someone to come and tame it, positive integers can be broken down as sums of consecutive positive integers in various ways. For example, the integer 42 often used as placeholder in this kind of discussions can be broken down into such a sum in four different ways: (a) 3 + 4 + 5 + 6 + 7 + 8 + 9, (b) 9 + 10 + 11 + 12, (c) 13 + 14 + 15 and (d) 42. As the last solution (d) shows, any positive integer can always be trivially expressed as a singleton sum that consists of that integer alone. Given a positive integer n, determine how many different ways it can be expressed as a sum of consecutive positive integers, and return that count. The count of how many different ways a positive integer n can be represented as a sum of consecutive integers is also called its politeness, and can be alternatively computed by counting how many odd divisors that number has. However, note that the linked…ion C Lons Employee -id: int -name String - dob : Date -staff : ArrayList +setid(int): void +getld() : int +setName(String): void +setDob(Date) : void +getDob(): Date +addStaff(Employee) : void +getStaff() : ArrayList
- Python coding language Create a static dictionary with a number of users and with the following values: First name Last name Email address Password Ask the user for: 5. Email address 6. Password Loop (for()) through the dictionary and if (if()) the user is found print the following: 7. Hello, first name last name you have successfully logged in 8. Notify the user if the password and email address are wrong 9. Additional challenge: if you want the program to keep asking for a username and password when the combination is wrong, you will need a while() loop. 10. Save the file as assignment03yourlastname.py#ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #define NAME_LEN 25 #define MAX_PARTS 100 struct part { int number; char name[NAME_LEN + 1]; int on_hand; double price; } inventory[MAX_PARTS]; int num_parts = 0; int find_part(int number); void insert(void); void search(void); void update(void); void print(void); int read_line(char str[], int n); int main(void) { char code; for (;;) { printf("Enter operation code: "); scanf(" %c", &code); while (getchar() != '\n') /* skips to end of line */ ; switch (code) { case 'i': insert(); break; case 's': search(); break; case 'u': update(); break; case 'p': print(); break; case 'q': return 0; default: printf("Illegal code\n"); } printf("\n"); } } int find_part(int number) { int i; for (i = 0; i < num_parts; i++) if…
- if L1={ab,b} L2={abb,bb} then L1L2= * O {ababb,abbb,abbab,bbab} O {ab,b,abb,bb} O {ababb,abbb,babb,bbb} O {abbab,abbb,bbab,bbb}dictionaries = [] dictionaries.append({"First":"Bob", "Last":"Jones"}) dictionaries.append({"First":"Harpreet", "Last":"Kaur"}) dictionaries.append({"First":"Mohamad", "Last":"Argani"}) for i in range(0, len(dictionaries)): print(dictionaries[i]['First']) ************************************************* please modity the above code to "Add an ‘if’ statement(s) to the loop in your solution in Exercise 7 to only show the full name if the first name is “Bob” or if the last name is “Kaur”.C programming pseudocode pointers help. { totalInAGivenHour+=*(rawReadings+ monthNo*30*14*4 + 14*4*nThDateOfMonth+ 4*nThHourOfDateFrom7AM + nThReadingTimeOfHour); // the pointer is to assign the values in the bracket and storing them in totalInAGivenHour }
- dictionaries = [] dictionaries.append({"First":"Bob", "Last":"Jones"}) dictionaries.append({"First":"Harpreet", "Last":"Kaur"}) dictionaries.append({"First":"Mohamad", "Last":"Argani"}) for i in range(0, len(dictionaries)): # Condition that's print the full name when Condition is True if(dictionaries[i]['First']=='Bob')or(dictionaries[i]['Last']=='Kaur'): print(dictionaries[i]['First']+" "+dictionaries[i]['Last']) ********************************** please modify the code to use a while loop instead of a for loopC CodeApproved Libraries:<string.h> *not allowed in some questions<math.h><stdlib.h><time.h> (for srand(time(0)) only)#ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;}; bool DelOddCopEven(Node* headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endif // definition of DelOddCopEven of Assignment 5 Part 1//Algorithm should: /*NOT destroy any of the originally even-valued node. This means that the originally even-valued nodes should be retained as part of the resulting list. Destroy…
