Consider a 200.0 mL solution that is 0.00155 M in HCl and 0.0200 M in HCIO2 wwww a) Calculate the pH. b) The amount of NaOH at 0.16 g is added to the solution. (Assume no change in volume) Calculate the pH.

Appl Of Ms Excel In Analytical Chemistry
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Chapter7: Neutralization Titrations And Graphical Representations
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Step 1: The ICE table should be modified as below:

(M)      HClO2(aq) + H2O(l)   H3O+(aq)   + ClO2-(aq)

I           0.0200             ---           0.00155          0

C            - x                  ---              + x               + x

E         0.0200 - x        ---          0.00155 + x       x

 

Step 2: Then using the values at equilibrium (E), set up the expression for Ka of HClO2.

Step 3: Solve for x by using the quadratic equation. 

Step 4: [H3O+] = 0.00155 + x

              pH = - log[H3O+]

2. Consider a 200.0 mL solution that is 0.00155 M in HCl and 0.0200 M in HCIO2
a) Calculate the pH.
b) The amount of NaOH at 0.16 g is added to the solution.
(Assume no change in volume)
Calculate the pH.
Transcribed Image Text:2. Consider a 200.0 mL solution that is 0.00155 M in HCl and 0.0200 M in HCIO2 a) Calculate the pH. b) The amount of NaOH at 0.16 g is added to the solution. (Assume no change in volume) Calculate the pH.
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