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Consider Ohm's law, V = IR, where V is the voltage, I is the current, and R is the resistance. Solve the equation V = IR for I. V I = R Determine dI dt V dv + dt R² dR dt The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I dv dR is changing (in A/s) at the moment when R = 323, I = 0.02 A, = -0.05 V/s, and = 0.04 2/s. (Round your answer to six decimal places.) dt dt 88 dI = dt ( LR A/s

Consider Ohm's law, V = IR, where V is the voltage, I is the current, and R is the resistance. Solve the equation V = IR for I. V I = R Determine dI dt V dv + dt R² dR dt The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I dv dR is changing (in A/s) at the moment when R = 323, I = 0.02 A, = -0.05 V/s, and = 0.04 2/s. (Round your answer to six decimal places.) dt dt 88 dI = dt ( LR A/s

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter12: Quadratic Functions
Section12.8: Joint And Combined Variation
Problem 8P
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Consider Ohm's law, V = IR, where V is the voltage, I is the current, and R is the resistance. Solve the equation V = IR for I. V I = R Determine dI dt V dv + dt R² dR dt The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I dv dR is changing (in A/s) at the moment when R = 323, I = 0.02 A, = -0.05 V/s, and = 0.04 2/s. (Round your answer to six decimal places.) dt dt 88 dI = dt ( LR A/s
Transcribed Image Text:Consider Ohm's law, V = IR, where V is the voltage, I is the current, and R is the resistance. Solve the equation V = IR for I. V I = R Determine dI dt V dv + dt R² dR dt The voltage V in a simple electrical circuit is slowly decreasing as the battery wears out. The resistance R is slowly increasing as the resistor heats up. Use Ohm's law, V = IR, to find how the current I dv dR is changing (in A/s) at the moment when R = 323, I = 0.02 A, = -0.05 V/s, and = 0.04 2/s. (Round your answer to six decimal places.) dt dt 88 dI = dt ( LR A/s
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