Consider the circuit below, with R = 802, C₁ = 0.04F, L₁= 2H and L₂=3H, calculate the node voltages V₁ and V₂. Select the correct answer below with the angles in degrees. V₁ C₁ + L₁ 000000 Va R www 40 cos (5t -20°) V O V₁(t) = 39.92 cos(5t -22.81°) V; V₂(t) = 39.57 cos(5t -19.91°) V O V₁(t) = 40.15 cos(5t -22.59 °) V; V₂(t) = 39.99 cos(5t -16.88°) V O V₁(t) = 40.33 cos(5t-22.35 °) V; V₂(t) = 40.45 cos(5t-13.85°) V O V₁(t) = 40.74 cos(5t-18.09 °) V; V₂(t) = 44.65 cos(5t +2.47°) V O V₁(t) = 40.83 cos(5t-17.48 °) V; V₂(t) = 46.25 cos(5t +8.1 °) V O V₁(t) = 40.95 cos(5t -16.93°) V; V₂(t) = 48.29 cos(5t +13.1 °) V O V₁(t) = 42.11 cos(5t-10.44 °) V; V₂(t) = 75.45 cos(5t +36.60 °) V O V1(t) = 41.664 cos(5t -8.94°) V; V₂(t) = 80.47 cos(5t +44.61 °) V O V₁(t) = 41.53 cos(5t -7.74°) V; V₂(t) = 86.87 cos(5t +49.8 °) V V₁(t)=40.44 cos(5t-17.43°) V: V₂(t) = 45.91 cos(5t +8 36°) Y 45 www. L2 V₂ 3V₂
Consider the circuit below, with R = 802, C₁ = 0.04F, L₁= 2H and L₂=3H, calculate the node voltages V₁ and V₂. Select the correct answer below with the angles in degrees. V₁ C₁ + L₁ 000000 Va R www 40 cos (5t -20°) V O V₁(t) = 39.92 cos(5t -22.81°) V; V₂(t) = 39.57 cos(5t -19.91°) V O V₁(t) = 40.15 cos(5t -22.59 °) V; V₂(t) = 39.99 cos(5t -16.88°) V O V₁(t) = 40.33 cos(5t-22.35 °) V; V₂(t) = 40.45 cos(5t-13.85°) V O V₁(t) = 40.74 cos(5t-18.09 °) V; V₂(t) = 44.65 cos(5t +2.47°) V O V₁(t) = 40.83 cos(5t-17.48 °) V; V₂(t) = 46.25 cos(5t +8.1 °) V O V₁(t) = 40.95 cos(5t -16.93°) V; V₂(t) = 48.29 cos(5t +13.1 °) V O V₁(t) = 42.11 cos(5t-10.44 °) V; V₂(t) = 75.45 cos(5t +36.60 °) V O V1(t) = 41.664 cos(5t -8.94°) V; V₂(t) = 80.47 cos(5t +44.61 °) V O V₁(t) = 41.53 cos(5t -7.74°) V; V₂(t) = 86.87 cos(5t +49.8 °) V V₁(t)=40.44 cos(5t-17.43°) V: V₂(t) = 45.91 cos(5t +8 36°) Y 45 www. L2 V₂ 3V₂
Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter2: Fundamentals
Section: Chapter Questions
Problem 2.2P: Convert the following instantaneous currents to phasors, using cos(t) as the reference. Give your...
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Transcribed Image Text:Consider the circuit below, with R = 802, C₁ = 0.04F, L₁= 2H and L₂=3H, calculate the node
voltages V₁ and V₂. Select the correct answer below with the angles in degrees.
V₁
C₁
+
L₁
oooooo
Va
R
www
40 cos (5t -20°) V
O V₁(t) = 39.92 cos(5t -22.81°) V; V₂(t) = 39.57 cos(5t-19.91°) V
O V₁(t) = 40.15 cos(5t -22.59°) V; V₂(t) = 39.99 cos(5t -16.88°) V
O V₁(t) = 40.33 cos(5t-22.35 °) V; V₂(t) = 40.45 cos(5t-13.85°) V
O V₁(t) = 40.74 cos(5t -18.09 °) V; V₂(t) = 44.65 cos(5t +2.47°) V
O V₁(t) = 40.83 cos(5t-17.48 °) V; V₂(t) = 46.25 cos(5t +8.1 °) V
O V₁(t) = 40.95 cos(5t -16.93°) V; V₂(t) = 48.29 cos(5t +13.1 °) V
O V₁(t) = 42.11 cos(5t-10.44°) V; V₂(t) = 75.45 cos(5t +36.60 °) V
O V1(t) = 41.664 cos(5t -8.94°) V; V₂(t) = 80.47 cos(5t +44.61 °) V
O V₁(t) = 41.53 cos(5t -7.74°) V; V₂(t) = 86.87 cos(5t +49.8 °) V
V₁(t)=40.44 cos(5t-17.43°) V: V₂(t) = 45.91 cos(5t +8.36°) V
45
L2
oooooo
V₂
3V₁
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