Consider the finction f(x, y) = 6y² + 4x² – 12xy – 4y. Then: O0,1) is a critical point and f has a local maximum at (1,1) ONone of these (-1,-2/3) is a critical point and f has a local minimum at (-1,-2/3)

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Q: Consider the function f(x, y) = 6y + 4x? - 12xy- 4y. Then: O (1,1) is a critical point and f has a…

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

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Q: Consider the finction f(x, y) = 6y² + 4x² – 12xy- 4y. Then: (1,1) is a critical point and f has a…

A: The given function is f(x,y)=6y2+4x2-12xy-4y

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Q: Consider the function f(x, y) = 6y2 +4x2- 12xy- 4y. Then: O None of these O (1,-2/3) is a critical…

A: We have : f(x,y)=6y2+4x2-12xy-4y ⇒fx=8x-12y⇒fy=12y-12x-4 Now, for Calculating Critical points, we…

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Q: Consider the finction f(x, y) = 6y2 +4x2-12xy-4y. Then: %3D O None of these O (1,2/3) is a critical…

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