Consider the following code: Scanner console new Scanner(System.in); int sum = 0; int count = 1; while (count < 5 && console hasNext()) { int num= console.nextInt(): sum sum + num count count + 1; } double average = (double)sum/(count-1); System.out.printf("average = %.2fin, average). System.out.println("count="+count + sum + sum Supposed the input from the keyboard is 1 2 3 4 5 6 • What is the final value for average?
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- In C++ QUESTION 14 class rectangleType { public: void setLengthWidth(double x, double y); //Sets the length = x; width = y; void print() const; //Output length and width double area(); //Calculate and return the area of the rectangle (length*width) double perimeter(); //Calculate and return the perimeter (length of outside boundary of the rectangle) private: double length; double width; }; Write the function definition for the function perimeter#include tinclude 3 tinclude 4 void modify(int *, int) ; 5 int main (void) int sensor[15]; int i, thr = 15; for (i=0;i<15;i++) * (sensor+i)=rand () *100; 8 10 11 printf("Sensor Value\n"); for (i=0;i<15;i++) printf("%3d",* (sensor+i)); modify(sensor,thr); printf("\nAfter Modification\n"); for (i=0;i<15;i++) printf("%3d",*(sensor+i)); return 0; 13 14 15 16 17 18 19 20 L} 21 22 void modify(int *d, int t) 23B { 24 int i; for (i=0;i<15;i++) 25 26 if (*(d+i) <= t) * (d+i) = t; 27 28 29 30 B Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification 41 67 34 12 69 24 78 58 62 64 12 45 81 27 61 41 67 34 20 69 24 78 58 62 64 25 45 81 27 61 D Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification Sensor Value 41 67 34 0 69 24 78 58 62 64 5 45 81 27 61 After Modification 41 67 34 15 69 24 78 58 62 64 15 45 81 27 61 61 87 54 20 89 44 98 78 82 84 25 65101 47 81 oao 123 456 r893: The code on the right is supposed to be the ARM code for procA; however, there are problems with the ARM code. C code: int procA(int x, int y) { int perimeter = (x + y) * 2; I return perimeter; } ARM code: I procA: add rø, r1, r2 mov r1, rø lsl #1 bx lr push {lr} Give the corrected version of the ARM code for procA:
- #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…#include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…
- #include<stdio.h>#include<stdlib.h> int cent50=0;int cent20=0;int cent10=0;int cent05=0; void calculatechange(int* change){if(*change>0){if(*change>=50){*change-=50;cent50++;}else if(*change>=20){*change-=20;cent20++;}else if(*change>=10){*change-=10;cent10++;}else if(*change>=05){*change-=05;cent05++;}calculatechange(change);}}void printchange(){if(cent50)printf("\n50cents:%d coins",cent50);if(cent20)printf("\n20cents:%d coins",cent20);if(cent10)printf("\n10cents:%d coins",cent10);if(cent05)printf("\n05cents:%d coins",cent05);cent50=0;cent20=0;cent10=0;cent05=0;}void takechange(int* change){scanf("%d",change);getchar();}int main(){int change=0;int firstinput=0;while(1){if(!firstinput){printf("\nEnter the amount:");firstinput++;}else{printf("\n\nEnter the amount to continue or Enter -1 to…int f(int &k){k++;return k * 2;}int main(){int i = 1, j = -1;int a, b, c;a = f(i) + i/2;b = j + f(j) + f(j);c = 2 * f(j);return 0;} What are the values of a, b and c id the operands in the expressions are evaluated from left to right and then what are the values when its evaluated right to left?int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…
- 1. #include int main() { int i; for (i = 1; i int main() { double number, sum = 0; do { printf("Enter a number: "); scanf("%lf", &number); sum += number; } while(number != 0.0); printf("Sum = %.2lf",sum); return 0; } }#include using namespace std; const int y = 1; int main () { int static y = 2; int i = 3, j = 4, m = 5, n = 6; %3D int a = [] (int x, int i = 1) { return x * i; } (y, 3) ; %3D int b = [=] (int x) { return [=] (int b) { return b + j; } (x) % 7; } (a); int c = [=] (int x) mutable ->int { m = 6; return [6] (int j) mutable { y = a * b; return y / j; } (x) -m; } (b) ; cout << a << endl; cout << b << endl; cout << c << endl; cout << m << endl; cout << y < endl; return 0; This program outputs 5 lines. What are they? Please explain your work and your answer.int pertambahan(int pilihan, int now){ int result; result =pilihan + now; return result;} int perkalian(int pilihan, int now){ int result; result = pilihan*now; return result;} int main(){ int NoR,initial; int now; int temp1, temp2; scanf("%d %d", &NoR, &initial); getchar(); now=initial; for(int o=0;o<NoR;o++){ char a,b; int pilihan1,pilihan2; scanf("%c %d %c %d",&a, &pilihan1,&b, &pilihan2); getchar(); if(a=='+') { if(pilihan1>=-1000 && pilihan1<=1000) { temp1 = pertambahan(pilihan1,now); } else{ temp1=-10000; } } else if(a=='x') { if(pilihan1>=-2 && pilihan1<=2){ temp1 = perkalian(pilihan1,now); } else { temp1=-10000; } } if(b=='+') { if(pilihan2>=-1000 && pilihan2<=1000) { temp2 = pertambahan(pilihan2,now); } else {…