Consider the half-wave rectifier shown below. It needs to deliver 0.1 A and an average of 15 V to a load. The source is 60 Hz and the diode has a 0.7 V drop. The allowable ripple is no more than 0.4 V (2.5%). Find: Peak AC voltage Vm of the source a) b) The minimum value of the smoothing capacitor(s) c) Comment on the type of capacitor and its/their values you would use for this amount of capacitance v₁(t) K+ C UL Load

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)
10th Edition
ISBN:9781337399128
Author:Russell E. Smith
Publisher:Russell E. Smith
Chapter12: Electronic Control Devices
Section: Chapter Questions
Problem 4RQ: What is the difference between a diode and rectifier?
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Consider the half-wave rectifier shown below. It needs to deliver 0.1 A and an average of 15 V to a load. The
source is 60 Hz and the diode has a 0.7 V drop. The allowable ripple is no more than 0.4 V (2.5%). Find:
Peak AC voltage Vm of the source
a)
b) The minimum value of the smoothing capacitor(s)
c) Comment on the type of capacitor and its/their values you would use for this amount of capacitance
vs(t)
K
Load
UL
Transcribed Image Text:Consider the half-wave rectifier shown below. It needs to deliver 0.1 A and an average of 15 V to a load. The source is 60 Hz and the diode has a 0.7 V drop. The allowable ripple is no more than 0.4 V (2.5%). Find: Peak AC voltage Vm of the source a) b) The minimum value of the smoothing capacitor(s) c) Comment on the type of capacitor and its/their values you would use for this amount of capacitance vs(t) K Load UL
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