Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices. As a consequence, the practical inductor above can be represented by it inductance L in series with the resistance of the coil R (calculated above). Let this equivalent R-L circuit be connected to a 12 V source that has an internal resistance of 0.5 Ω as shown on the right hand side of Figure 3. Let switch SW2 be in the open position, while SW1 closed at t = 0.    Nearly how long will it take the inductor to fully charge (i.e., reach steady-state)? 1) 1.5 sec 2) 100 msec 3) 18.5 min 4) 37 sec

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Consider the large inductor in Figure 3 with given number of turns N, core permeability μ, core cross section area A, and core diameter are given. Note that the core length l is equal to π times the core diameter. Answer the questions and pick an answer from the given choices.

As a consequence, the practical inductor above can be represented by it inductance L in series with the resistance of the coil R (calculated above). Let this equivalent R-L circuit be connected to a 12 V source that has an internal resistance of 0.5 Ω as shown on the right hand side of Figure 3. Let switch SW2 be in the open position, while SW1 closed at t = 0.    Nearly how long will it take the inductor to fully charge (i.e., reach steady-state)?

1) 1.5 sec

2) 100 msec

3) 18.5 min

4) 37 sec

Sw2
SW, m
H = 0.01 H/m
N = 100
50 cm
R.
12V
Core Area: 0.06 m?
#0.5
Figure 3 (Problem 3)
Transcribed Image Text:Sw2 SW, m H = 0.01 H/m N = 100 50 cm R. 12V Core Area: 0.06 m? #0.5 Figure 3 (Problem 3)
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