Consider the network depicted in Figure 1; suppose that each node starts with the
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Consider the network depicted in Figure 1; suppose that each node starts with the
behavior B, and each node has a threshold of q = 1/2 for switching to behavior A.
Find a cluster of density greater than 1 − q = 1/2 in the part of the graph outside S
that blocks behavior A from spreading to all nodes, starting from S, at threshold q
Step by step
Solved in 2 steps
- ADT Graph Iterator: Create either a DFS graph iterator or a BFS graph iterator by implementing java.util.lterator interface. An ADT graph iterator should have a reference to an ADT graph. It should also have a DFS search method or a BFS search method.Social Graph project is network which consists of two things : People is represented in the Graph by Nodes or Vertices (the vertex should consist of name of the person) Relationships is represented in the Graph by edges or arcsThe project should have at least two class with following methods : addNode add vertices to graphs(New person in the Graph Net )removeNode removes vertices to graphs(remove person from the graph Net)addEdge adds connections or paths between vertices in graphs(make new relationship between two persons in the graph )removeEdge removes connection or paths between vertices in graphs (remove the relationship between two persons in the graph )contains check if a graph contains a certain valuehasEdge checks if a connection or path exists between any two vertices in a graph IN JAVA LANGUAGESocial Graph project is network which consists of two things : People is represented in the Graph by Nodes or Vertices (the vertex should consist of name of the person) Relationships is represented in the Graph by edges or arcsThe project should have at least two class with following methods : addNode add vertices to graphs(New person in the Graph Net )removeNode removes vertices to graphs(remove person from the graph Net)addEdge adds connections or paths between vertices in graphs(make new relationship between two persons in the graph )removeEdge removes connection or paths between vertices in graphs (remove the relationship between two persons in the graph )contains check if a graph contains a certain valuehasEdge checks if a connection or path exists between any two vertices in a graph IN JAVA LANGUAGE PLEASE and thnak you !
- To finish up the definition of the Node class, we need at least two constructor methods. We definitely want a default constructor that creates an emptyNode, with both the Element and Link members set to null. We also need aparameterized constructor that assigns data to the Element member and setsthe Link member to null.Write the code for the Node class:1. The below method is used to select a nodein map coloring problem.def get_node():mnode = "length = -1for k in cgraph.keys():if(len( cgraph[k]) > length and k not inok Color.keys());length = len(cgraph[k])mnode = kreturn mnode The method will return an empty string when A. All nodes are already assigned colorsB. There is no color remaining for a nodeC. Any two nodes have only one color left Note: Select 1 answer from 3 options.starter code: in java pls and thank you! public class LinkedList { private Node head; private Node tail; public void add(String item) { Node newItem = new Node(item); // handles the case where the new item // is the only thing in the list if (head == null) { head = newItem; tail = newItem; return; } tail.next = newItem; tail = newItem; } public void print() { Node current = head; while (current != null) { System.out.println(current.item); current = current.next; } } public void printWithSkips() { // TODO your code here } class Node { String item; Node next; public Node(String item) { this.item = item; this.next = null; } } } and public class Driver { public static void…
- class Node { public: Node() : data(0), prev(nullptr), next(nullptr) {} Node(int theData, Node* prevLink, Node* nextLink) : data(theData), prev(prevLink), next(nextLink) {} int getData() const { return data; } Node* getPrev() const { return prev; } Node* getNext() const { return next; } void setData(int theData) { data = theData; } void setPrev(Node* prevLink) { prev = prevLink; } void setNext(Node* nextLink) { next = nextLink; } ~Node(){} private: int data; Node* prev; Node* next; }; class AnyList { // friend function overloads the insertion operation public: // copy constructor // overloaded assignment operator // other member functions not necessary for your implementation private: Node *first; Node *last; int count; }; please help write copy constructor #include "AnyList.h" #include <iostream> using namespace std; // Definition of copy constructor // Instructions omitted intentionally. // Your codeQ8 Hive Minds: Migrating Birds You again control a single insect, but there are B birds flying along known paths. Specifically, at time t each bird b will be at position (x¿(t), Yb(t)). The tuple of bird positions repeats with period T. Birds might move up to 3 squares per time step. An example is shown below, but keep in mind that you should answer for a general instance of the problem, not simply the map and path shown below. Your insect can share squares with birds and it can even hitch a ride on them! On any time step that your insect shares a square with a bird, the insect may either move as normal or move directly to the bird's next location (either action has cost 1, even if the bird travels farther than one square).public class Node extends Object { public T data; public Node next; public Node () { data = null; next = null; } public Node (T val) { data = val; next = null; }} public class LinkList extends Object { private Node head; private Node current; public LinkList (){ head = current = null; } public boolean empty () { return head == null; } What does the fpllowing code do? public Node remove() { if (empty()) return null; Node temp,c; c = head; while(c.next != null) temp = c; c = c.Next; } temp.next = null; size--; return c;
- If no node was encountered more than once, then the set of nodes and elements that we have passed through is defined as a closed path. Select one: True False1-Let’s say you have a variable with a static graph associated with it in the backend that will be executed every time you call .compute on that variable. Is there any way to avoid re-computation of the graph every time you call the .compute method? Consider that you have a significant amount of storage available in this case.JavaScript The jQuery "post" method that we used in this course to enable "round-trip" dialog with the node.js server has the form: $.post("/", x, y); Describe the type and purpose of the x and y parameters.