Consider the nuclide cobalt-59 (5927Co). (a) The mass of 5927Co in atomic mass units is 58.933200 u. (Note this is the mass of the entire atom, not just the nucleus.) This mass is lower than the total mass of its constituent protons, neutrons, and electrons. Find the difference, in atomic mass units, between the total mass of the constituent particles, and the actual mass of the nuclide. (This is sometimes called the "mass defect.") The mass of a proton is 1.007276 u, the mass of a neutron is 1.008665 u, and the mass of an electron is 5.486 ✕ 10−4 u. (Round your answer to at least four decimal places.)   b) Since, according to special relativity theory, mass and energy are "equivalent," the mass defect, or "missing" mass found in part (a), is measurement of the energy it would take to break the bound 5927Co atom into its constituent particles. In other words, it is equivalent to the binding energy. Using the result of part (a), find the binding energy per nucleon, Eb/A  for 5927Co in units of MeV. (Round your answer to at least two decimal places.)

Chemistry: The Molecular Science
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Chapter1: The Nature Of Chemistry
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Consider the nuclide cobalt-59 (5927Co).

(a)
The mass of 5927Co in atomic mass units is 58.933200 u. (Note this is the mass of the entire atom, not just the nucleus.) This mass is lower than the total mass of its constituent protons, neutrons, and electrons.
Find the difference, in atomic mass units, between the total mass of the constituent particles, and the actual mass of the nuclide. (This is sometimes called the "mass defect.") The mass of a proton is 1.007276 u, the mass of a neutron is 1.008665 u, and the mass of an electron is 5.486 ✕ 10−4 u. (Round your answer to at least four decimal places.)
 
b) Since, according to special relativity theory, mass and energy are "equivalent," the mass defect, or "missing" mass found in part (a), is measurement of the energy it would take to break the bound 5927Co atom into its constituent particles. In other words, it is equivalent to the binding energy.
Using the result of part (a), find the binding energy per nucleon, Eb/A
 for 5927Co in units of MeV. (Round your answer to at least two decimal places.)
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